MHB Help find eqn of circle given another circle that is tangent

  • Thread starter Thread starter sktrinh
  • Start date Start date
  • Tags Tags
    Circle Tangent
AI Thread Summary
The discussion focuses on finding the equations of two circles with a radius of 10 that are tangent to the circle defined by X^2 + y^2 = 25 at the point (3,4). The centers of the circles are determined to be at (-3,-4) and (9,12), both of which are 10 units away from the tangent point along the line y = 4/3x. The participants explore algebraic methods to derive these centers using distance formulas and the relationship between the coordinates. The final equations of the circles are established as (x-9)^2 + (y-12)^2 = 100 and (x+3)^2 + (y+4)^2 = 100. The discussion concludes with a confirmation of the centers and their respective equations.
sktrinh
Messages
3
Reaction score
0
please help me find the standard equation of the circles that have radius 10 and are tangent to the circle X^2 + y^2 = 25 at the point (3,4).

the soln: (x-9)^2 + (y-12)^2 = 100, (x+3)^2 + (y+4)^2 = 100,

i found the eqn that intersects the centre of the small circle and the larger one to be: y=4/3x, substituted as k=4/3k for C(h,k) into the eqn of the circle, however require some help solving it. thanks!
 
Mathematics news on Phys.org
I would simply observe that the center of one circle must be at (-3,-4) and the other at (9,12). These points are both 10 units from the tangent point along the line you correctly found.
 
MarkFL said:
I would simply observe that the center of one circle must be at (-3,-4) and the other at (9,12). These points are both 10 units from the tangent point along the line you correctly found.

is there a algebraic way of solving it using distance formulas like d = |ax+by+c|/sqrt(a^2+b^2°+) or something else?

I solved for eqn of line of the that passes thru both the small and large circle being y=4/3x, and set k=4/3h since it passes thru the large circle as well (i think), with this expression i plugged into (3-h)^2 + (4-k)^2 = 100

(3-h)^2 + (4-4/3h)^2 = 100

I couldn't solve this thru, i keep getting h^2 -6h -9, which i think shud be h^2 -6h + 9, so that h = -3 and which would follow k = -4. How would I solve in a similar fashion for the second large circle as impled by the solution of C(9,12)??
 
Well, we know the centers of all circles will lie on the line:

$$y=\frac{4}{3}x$$

And so the center of the two tangent circles will be at:

$$(h,k)=\left(h,\frac{4}{3}h\right)$$

And since the must both pass through the point $(3,4)$, we may state:

$$(3-h)^2+\left(4-\frac{4}{3}h\right)^2=100$$

$$(3-h)^2+\frac{16}{9}\left(3-h\right)^2=100$$

$$\frac{25}{9}\left(3-h\right)^2=100$$

$$\left(h-3\right)^2=6^2$$

$$h=3\pm6$$

This implies:

$$h=-3,\,9$$

And using the relation between $h$ and $k$, which is $$k=\frac{4}{3}h$$ , we then conclude the centers are at:

$$(-3,-4),\,(9,12)$$
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...

Similar threads

Back
Top