find the deflection of the beam at point B(adsbygoogle = window.adsbygoogle || []).push({});

i drew the free body diagram of the beam and found that

Ay=0

Ax=qL

Cy=qL

Cx=qL

M(x)= (qL)*x - (qx)*x/2 +(qL)*<x-L/2>

M(x)=(qL)x -(q/2)x^{2}+(qL)<x-L/2>

EIΦ(x)=(qL/2)x^{2}-(q/6)x^{3}+(qL/2)<x-L/2>^{2}+ C1

EIY(x)=(qL/6)x^{3}-(q/24)x^{4}+(qL/6)<x-L/2>^{3}+ C1*x + C2

EIY(0)=0= 0+ C2

===>c2=0

but i need another condition to find C1, i think i need to use the deflection of the bar DC somehow, but im not quite sure how, i tried using triangles and saying that the deflection of point C is the same as the deflection of the bar DC*sin(45) but that didnt work

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# Help finding deflection of beam

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