Help finding radius for the torque

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    Radius Torque
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Homework Help Overview

The discussion revolves around finding the radius for torque in a scenario involving a beam and a cable. The original poster is attempting to relate the radius to the length L and is exploring the relationship between the force acting on the beam and the geometry of the setup.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are discussing the definition of radius in the context of torque and whether trigonometry is necessary to relate the radius to the length L. There are questions about the relationship between the pivot point, the force acting on the beam, and the geometry involved.

Discussion Status

There is an ongoing exploration of the definitions and relationships involved in the problem. Some participants have provided guidance on the definition of radius, while others are questioning the assumptions made about the geometry and the points of force application.

Contextual Notes

Participants are navigating the definitions of torque and radius, and there is a focus on the geometry of the setup, including the angles involved and the points of force application. The original poster's diagram and the specific angles mentioned may influence the discussion.

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Homework Statement


PnLnY.png



Homework Equations


Torque = Force * radius * sin(angle)


The Attempt at a Solution



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I am trying to find the radius for the torque of the cable, but I can't seem to use any trig to solve for that side in terms of L.
 
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The radius is L,
you do not need any trigonometry.
remember, radius (when referring to torque) is defined as the distance from the pivot point to the point that the force is acting on - in other words - L.
 
The pivot point to the point that the force is acting on is marked in my diagram by 'R'. I don't see how R = L
 
The wire is pulling on the beam with a tension, this is the force in question. The point that you have marked as the point that the force is acting upon is on the wire itself. In order to cause a torque on the beam the force must be acting on the beam itself, not the wire.
 
I don't understand what you are saying. The force of the Tension is acting on the beam. The axis of rotation is the hinge. So, we need the distance from the Tension to the axis of rotation. To do that, we use the perpendicular distance created from the axis of rotation to the Tension. Isn't that what we want?
 
You have a right triangle where L is the hypotenuse and R is the side opposite the 30-degree angle. What trig function relates side opposite and hypotenuse?
 
Ah, I see the sine function now. Thanks
 

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