Help finding the spring constant in a magnetic field

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Homework Help Overview

The problem involves a wire loop situated in a magnetic field, where the loop experiences torque due to an electric current. The objective is to determine the spring constant based on the compression of a spring caused by this torque.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of torque equations and the relationship between torque, force, and spring constant. There are attempts to derive the spring constant using different formulations, and questions arise regarding the choice of dimensions and components of the magnetic field affecting the loop.

Discussion Status

Participants are actively engaging with the problem, sharing attempts and questioning each other's reasoning. Some guidance has been offered regarding the interpretation of the magnetic field's effect on the loop and the relevance of specific dimensions in calculations.

Contextual Notes

There is a mention of a diagram that may provide additional clarity, and participants are exploring the implications of the loop's dimensions on the calculations. The discussion reflects uncertainty about the correct application of formulas and the physical setup of the problem.

enforcer53
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Homework Statement


Consider a wire loop in a 1.88 T magnetic field (coming out of the board at a 55.0° angle). The loop is 0.300 m tall and 0.400 m wide, carrying a 2.90 A current traveling in a clockwise direction. The loop feels a torque that causes the spring to compress. If the spring is compressed by 4.30 mm, what is the spring constant?


The attempt at a solution
This is what i tried. I don't feel I am getting the right answer.

Torque is T = IABsinθ
(2.90 A)(0.120 m^2)(1.88 T)sin(55.0) =0.536

I know that Torque is also = Frsinθ
I then rearranged the formula to get F = Torque/rsinθ (0.536)/(0.15)(sin55) = 4.36 = F

I plug my Force value into the F=kx formula. In order to find k, I did (4.36)/(0.0043) which gave me k = 1013.9

This does not seem correct to me. Where did I go wrong?
 
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Hi enforcer53,

I think we'd need to see the diagram.
 
Last edited by a moderator:
Here are the diagrams
 

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Okay. Where did you get this equation from:
Torque is T = IABsinθ

If you resolve B into a component normal to the plane of the loop and a component within the plane of the loop, you will, I think, see that as far as the current-carrying-loop is concerned, only one side contributes a force which the spring can oppose.
 
I got the IABsinθ equation from class. I gave this problem another try.

I set it up so Kx = ILBsinθ. I rearranged to get K = ILBsinθ/x... Plug and chug (2.90)(0.400)(1.88)(sin55)/(0.0043) = 415.4

Am I getting closer?
 
How did you decide what value to use for L?
 
The dimensions of the loop are 0.400 and 0.300. So I used the length of 0.400
 
enforcer53 said:
The dimensions of the loop are 0.400 and 0.300. So I used the length of 0.400
Why did you decide on 0.400?
 
enforcer53 said:
The dimensions of the loop are 0.400 and 0.300. So I used the length of 0.400

Ah, but what is the length of the side of the current in which we are concerned with in opposing the spring?
 

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