- #1
sanado
- 56
- 0
After studying amplifiers and their operation, i suddenly realized today that i don't really know how they work at all.
Assume Vcc = 6V for an NPN transistor, biased correctly to fluctuate about 3V
In the Vout, once the DC part has been removed, how can the voltage possibly go lower than 0. If the amplifier is earthed, then isn't the minimal possible voltage 0? Wouldn't the V out at this point then be clipped and become 0? From the questions I've seen it obviously isn't but i don't understand why...Please help
Assume Vcc = 6V for an NPN transistor, biased correctly to fluctuate about 3V
In the Vout, once the DC part has been removed, how can the voltage possibly go lower than 0. If the amplifier is earthed, then isn't the minimal possible voltage 0? Wouldn't the V out at this point then be clipped and become 0? From the questions I've seen it obviously isn't but i don't understand why...Please help