Help Me Factorise: 3(n+r)(n+r-1) + (n+r) to (n+r)(3n+3r-2)

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Discussion Overview

The discussion revolves around the process of factorization in algebra, specifically transitioning from the expression 3(n+r)(n+r-1) + (n+r) to (n+r)(3n+3r-2). Participants seek clarification on the steps involved in this factorization process.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant requests a slow explanation of how to factor the given expression.
  • Another participant suggests that the term (n+r) is already factored out and encourages focusing on that to simplify the expression.
  • A third participant provides examples of factorization and suggests that understanding the reverse process (expanding) can aid in confirming the factorization steps.
  • This participant proposes substituting n+r with x to simplify the factorization process and outlines steps to factor out x from the expression.
  • A later reply indicates that the explanation was helpful and that the participant now understands the process.

Areas of Agreement / Disagreement

Participants generally agree on the approach to factorization, with some providing examples and methods to clarify the process. However, the discussion does not resolve any broader disagreements about factorization techniques.

Contextual Notes

The discussion assumes familiarity with basic algebraic concepts such as factorization and expansion, but does not delve into specific definitions or limitations of the terms used.

Who May Find This Useful

Students seeking assistance with algebraic factorization, particularly those looking for step-by-step explanations and examples.

confused88
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Can someone please help me with very simple math.. and explain slowly how they got from
3(n+r)(n+r-1) + (n+r)
to (n+r)(3n+3r-2)?

I forgot how to factorise, so can someone help me do this please?
 
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The n+r is already factored out. Just write everything in terms of that and you'll see.

(It's actually easier to understand by doing, in this case, than to have it explained!)
 
Explain slowly you say? Maybe that can be expressed through example.

ab+ac=a(b+c)
xy+x=x(y+1)
pqr+r=r(pq+1)

If you understand how to do the opposite of factorising which is expanding, then these results would be easy to confirm.

So for 3(n+r)(n+r-1) + (n+r)
let n+r=x
So we now have 3x(x-1)+x
Factorising x out: x(3(x-1)+1)
Expand 3(x-1) and collect like terms, then substitute n+r=x back into the result.
 
Oh wow i get it now. Thank you!
 

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