Help Me Find # of Onto Functions from B -> B

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Homework Help Overview

The discussion revolves around determining the number of onto functions from the set B = {1, 2, 3, 4, 5} to itself. Participants are exploring the properties of onto functions and their relationship to one-to-one functions in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the definition of onto functions and the implications of mapping elements from set B to itself. There is an exploration of the total number of functions and the conditions required for a function to be onto, including the necessity of being one-to-one.

Discussion Status

The discussion is active, with participants providing insights into the nature of onto functions and questioning the relationship between onto and one-to-one functions. Some participants express understanding of the mapping process, while others seek clarification on specific aspects of the function's properties.

Contextual Notes

There is an emphasis on the requirement that for a function to be onto, it must also be one-to-one, which is a key point of discussion. Participants are also considering the implications of mapping elements to themselves.

James889
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Hi,

I have a simple question i'd like some help with

let [tex]B = \{1,2,3,4,5\}[/tex]

How many functions from B -> B are onto ?

A kick in the right direction would be nice
 
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say you have a function defined on
[tex]f : a \in A \rightarrow f(a) = b \in B[/tex]

A function is onto if for every b in B, there exists an a, such that f(a) = b

in this case A = B
[tex]f : b \in B \rightarrow f(b) = b' \in B[/tex]
and there must be a b for every b'

so what else can you say about f?
 
There are, of course, 55 functions from B to B.

In order to be onto, a function from two sets of the same size (which, of course, includes functions from one set to itself) must also be one-to-one. I think that makes the problem simpler.

Choose a number to map "1" to - you have 5 choices. Once that is done, you cannot map anything else to that so you now have 4 choices to map "2" to, 3 to map "3" to, etc. See the point?
 
HallsofIvy said:
There are, of course, 55 functions from B to B.

In order to be onto, a function from two sets of the same size (which, of course, includes functions from one set to itself) must also be one-to-one. I think that makes the problem simpler.

Choose a number to map "1" to - you have 5 choices. Once that is done, you cannot map anything else to that so you now have 4 choices to map "2" to, 3 to map "3" to, etc. See the point?

I see the point, so an element can map to itself?
So is the function also one-to-one ?
 

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