Help me to demonstrate and explain: Vrs=r∇s+s∇r and ∇.sv=(VS.v)+s(∇.v)

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The expressions Vrs = r∇s + s∇r and ∇·sv = (VS·v) + s(∇·v) are derived using the product rule for derivatives, which is essential in transport phenomena and fluid mechanics. The discussion highlights the importance of clearly defining variables, where r and s are scalar fields, and v is a vector field. Understanding these expressions is crucial for applications in fluid dynamics and related fields.

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mark_usc
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Dear all:

Please help me to know how these expressions are obtained. Please recommendme some web reference to search more about the demonstrations.

Vrs=r∇s+s∇r

∇.sv=(VS.v)+s(∇.v)

This expressions are very important in transport phenomena and fluid mechanics.

With all the best

Marco Uscanga
 
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Why did you write "V" in two places? Did you mean ∇? Are r and s scalar fields, and v a vector field? You should explain these things when you ask for help. Is "S" a typo?

##\nabla (rs)## is a vector whose ith component is ##\partial_i(rs)##. Use the product rule for derivatives.

##\nabla\cdot (sv)=\sum_i\partial_i(sv)_i =\sum_i\partial_i(sv_i)##. Now use the product rule again.
 
it seems good to me. Thanks a lot

Marco Uscanga
 

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