Help Neede On Related Rates (conical Cistern)

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SUMMARY

The discussion focuses on calculating the rate at which the water level rises in a conical cistern with a height of 12 feet and a radius of 6 feet, given that water is entering at a rate of 8 ft³/min. The key equation involved is the volume of a cone, V = (1/3)πr²h, and the relationship between the radius and height of the water level is established through similar triangles. Participants emphasize the importance of understanding how to transition from a static volume formula to a dynamic rates formula to solve the problem effectively.

PREREQUISITES
  • Understanding of calculus concepts, particularly related rates
  • Familiarity with the volume formula for a cone: V = (1/3)πr²h
  • Knowledge of similar triangles and their applications in geometry
  • Ability to differentiate functions with respect to time
NEXT STEPS
  • Study the concept of related rates in calculus
  • Learn how to apply the volume formula for cones in dynamic scenarios
  • Explore the use of similar triangles in solving geometric problems
  • Practice problems involving rates of change in real-world contexts
USEFUL FOR

Students studying calculus, particularly those focusing on related rates, as well as educators looking for examples to illustrate the application of geometric principles in dynamic situations.

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At a rate of 8ft^3/min, water is pouring into a conical cistern, if the height of a cistern is 12ft and the radius of it's circular opening is 6ft, how fast is the water level rising when the water is 4ft deep?
 
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Having someone do the problem for you is not "help". What have you done? Do you know the equation for the volume of a cone in terms of height and radius? Do you see the relationship between height and radius of the water at any time in a cistern that is "12 ft high and radius 6 ft"? (draw a picture and think "similar triangles".)

Do you know how to go from a "static" formula (volume of cone) to a "rates" formula (how fast volume is changing)?
 

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