Help Needed: Cracking the Nut of Current in Field/Armature

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Discussion Overview

The discussion revolves around determining the current in the field or armature of a DC shunt motor. Participants explore various approaches to connect known values and equations to find the unknown currents, focusing on concepts such as Kirchhoff's Voltage Law (KVL), Kirchhoff's Current Law (KCL), and power calculations.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant expresses difficulty in connecting the dots to find the current in the field or armature.
  • Another participant suggests starting with a circuit diagram and labeling known voltages and currents to apply relevant equations.
  • A participant mentions having the supply current but struggles with understanding the relationship between current and resistors.
  • One participant believes that finding the current is essential for applying KVL, which would help in determining the armature current and subsequently the field current using KCL.
  • Another participant advises finding excitation losses and comparing them with excitation voltage drop.
  • A participant confirms that in a DC shunt motor, the field supply source is parallel with the armature.
  • One participant discusses the relationship between output power, losses, and input power, emphasizing the need to identify where losses occur and their corresponding formulas.
  • A later reply highlights the importance of back-emf in the calculations.
  • Another participant calculates the input power using the efficiency formula based on rated power and expresses confidence in determining the armature current and subsequently the field current using KCL.
  • One participant provides a mathematical equation involving armature and field currents, suggesting a quadratic form to solve for the currents.

Areas of Agreement / Disagreement

Participants express various approaches and calculations, but no consensus is reached on a singular method or solution. Multiple competing views and uncertainties remain regarding the relationships between currents and losses.

Contextual Notes

Some participants reference specific formulas and concepts, but there are limitations in the clarity of assumptions and definitions, particularly regarding losses and their impact on current calculations.

nooby
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Homework Statement
A D.C. shunt motor has an efficiency of 92.21 % when operated under full-load conditions. The motor is supplied by a 120 V D.C. source and has a rating of 1.55 kW at full-load. Given that the armature resistance of the motor is 0.33 Ω, find the resistance of the field winding. (You may neglect all losses other than those due to the armature and field winding resistances.)

Note – the rated power of a motor is the output power under full-load conditions.
Relevant Equations
efficiency and or power at full load
Hi all, I'm needing help cracking this nut. If someone can help it would be greatly appreciated.

I am trying to find the current in the field or armature, but can't connect the dots.
 
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As per forum rules, you need to show your attempt at a solution first.

Start with a circuit diagram.
Label the known voltages and currents. Think of the relavant equations that you can use to find the unknowns.
 
i got the supply current, but can't seem to understand the current and resistor relationship.
 

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the reason why i think i need the current is so i can use KVL. This will assist me in finding current in armature which i can then use KCL to find the current in the field. I got a feeling I'm chasing something that isn't there :(
 
Find the excitation losses. Compare with excitation voltage drop.
 
DC Shunt motor that means the field supply source is parallel with armature?
 
Pel=Pmec+losses
 
nooby said:
i got the supply current
The power you used in your equation is the 'output' power. To calculate the source current, you must know the 'input' power.
Output power + losses gives you the input power.
So identify where the losses are taking place and recall/look up their corresponding formulae.
Further, have you studied the concept of back-emf?
 
I had a closer read of the question, it states "Note – the rated power of a motor is the output power under full-load conditions."
so by using the efficiency formula to work out Power input (1680.9W).Which means i can work out the current the total current. This then allows me to work out the current in the armature which. Then i simple use KCL to work out the field current :)

hope that makes sense :)

Thanks you all for your assistance
 
  • #10
You may use the equation Is=Iarm+If and RA.Iarm^2+Rf.If^2=losses

Rf.If^2=Vs.If

and you'll get an equation like: a.Iarm^2+b.Iarm+c=0
 

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