Just starting out on DC motors and hit a snag

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SUMMARY

The discussion focuses on calculating the torque and operating efficiency of a series DC motor connected to a 230V supply, running at 1320 revolutions per minute (rev/min) with an output power of 3.8kW and a supply current of 20.5A. The key equations involved are Power = Torque * Angular Velocity and the efficiency calculation, which is the ratio of output power to input power expressed as a percentage. The input power can be derived from the supply voltage and current, allowing for the determination of both torque and efficiency using the provided data.

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carolinern
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Hi Guys
I'm hoping someone can help me out with a problem??
I have just started learning about DC motors and I have hit a wall on how to solve the following problem-

Q.The output of a series d.c. motor when connected to a 230V supply and running at 1320rev/min is 3.8kW. The supply current for this loading is 20.5A.
Calculate the torque developed and the opperating efficiency??

Can anyone explain the equations i need to be looking at, as I thought you needed the armature current and field current to be able to solve this??

Any advice or help is much appreciated

Cas
 
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You can solve this with conservation of energy. Find the input power (easy for DC), find a way to express output power with angular frequency and torque.
 
carolinern said:
Q.The output of a series d.c. motor when connected to a 230V supply and running at 1320rev/min is 3.8kW. The supply current for this loading is 20.5A.

Calculate the torque developed

Power = torque * angular velocity......(1)

The problem gives you the output power and enough info to calculate the angular velocity. Just take care with the units.

If you have difficulty remembering that equation perhaps remind yourself of the similar equations for linear motion..

Work = force * displacement
Power = work/time
so
power = force * displacement/time
but
displacement/time = velocity
so
Power = force * velocity.........(2)

see the similarity between (1) and (2)?

the operating efficiency?

The problem statement gives enough info to calculate the input power (electrical) and the output power is stated. Efficiency is one divided by the other expressed as a percentage.
 

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