Help Needed: Low Pass Filter Cutoff Frequency Closest to 100 kHz

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SUMMARY

The discussion focuses on selecting components for a low pass filter to achieve a cutoff frequency closest to 100 kHz. The relevant formula used is fc = 1 / (2π * R * C). The two combinations evaluated are: 1.6 kΩ with 1 nF, and 150 kΩ with 10 µF. The correct calculation reveals that the combination of 150 kΩ and 10 µF yields a cutoff frequency of approximately 106 Hz, which is closer to the target than the other options.

PREREQUISITES
  • Understanding of low pass filter design
  • Familiarity with the formula fc = 1 / (2π * R * C)
  • Knowledge of capacitor units (nF and µF)
  • Basic electrical component identification (resistors and capacitors)
NEXT STEPS
  • Calculate cutoff frequencies for various resistor and capacitor combinations
  • Explore the effects of different filter topologies on performance
  • Learn about the implications of component tolerances on filter design
  • Investigate simulation tools for electronic circuit design, such as LTspice
USEFUL FOR

Electronics enthusiasts, electrical engineers, and students studying circuit design who are interested in low pass filter applications and component selection.

blair321
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hi there

if anyone could help i would be very grateful

for a low pass filter

from the following list choose the two components which would produce a cut off frequency closest to 100 khz

resistor capacitor
1.6 k ohm 1 nf
33 k ohm 330 nf
150 k ohm 10 uf

formula being fc = 1 / 2pi * r * c

its the exact values for nf and uf that are posing the prob
 
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1.6k and 1 nf
 
nf = 10 to the ninth
uf = 10 to the sixth
 
many thanks
 
Originally posted by MaxMoon
nf = 10 to the ninth
uf = 10 to the sixth
I think you forgot some minus signs in there.

- Warren
 
Guess I did.
 

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