- #1

kiwimia

- 3

- 0

**1. Relevant information**

This is a two-block-system on top of each other to the right side of a wall, both attached with springs that are also attached to the wall. A force is applied on the bottom block to the right direction, frictions occurred on both bottoms of the two blocks. Here is the diagram illustration:

http://i62.tinypic.com/291ytxt.jpg

(BTW, don't worry about Weight = Mg, this can be ignored)

**2. Question**

Draw a free body diagram and determine the equations of motion for this system

## The Attempt at a Solution

This is the free body diagram I drew:

http://i60.tinypic.com/2zdqhpt.jpg

According to my free body diagram, I have the equation of motion for this system.

M2X2’’ + K2X2 + B2(X1’ – X2’) = 0

M1X1’’ + K1X1 + B1X1’ = f + B2(X1’ – X2’)

Does this seem right? Please let me know. Thanks!

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