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Help on Permuntation and Combination Question

  1. Oct 15, 2007 #1
    [SOLVED] Help on Permuntation and Combination Question

    1. The problem statement, all variables and given/known data

    After a show ,they decided to divide into two groups of size four and five, to go for a supper in 2 taxis. In how many ways could this be done if george and sally were to be in the same taxi

    2. Relevant equations

    3. The attempt at a solution

    No of ways = (3p3 x 2! + 4p4)+(2p2 x 2! + 5p5) = 160

    But answer is 56. How do u get the answer it is so small
  2. jcsd
  3. Oct 15, 2007 #2
    Taxi A and B have capacities 4,5 resp.

    They both (George, Sally) can be either in Taxi A or B. If they're in taxi A, how many more people do you have to select from 7 remaining and in how many ways? And in the second case (taxi B), how many more do you need from 7? Add them up to get your answer.

    You need to find the number of ways of selecting 2 and 3 people from 7. Can you see why? Also, the order in which you select the 2 or 3 doesn't matter. Also, the remaining people would occupy the second taxi. So you only need to consider the taxi in which Sally, George are sitting.

    The answer indeed is 56.

    Last edited: Oct 15, 2007
  4. Oct 15, 2007 #3
    OK Thanks so it was C instead of P. Question solved
  5. Oct 16, 2007 #4

    Gib Z

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    Homework Helper

    That doesn't sound like you really understand the situation, rather that you learn to insert things into equations :( To distinguish between a Permutation and a Combination, consider if order matters. For the taxis, it doesn't because if ABC get into 1 taxi, its the same as BAC etc etc.
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