Calculating Maximum Force in Periodic Motion: Airplane in a Storm

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The discussion focuses on calculating the maximum force acting on a passenger in an airplane subjected to vertical periodic motion during a storm. The airplane has a period of 30.2 seconds and an amplitude of 17.1 meters, leading to a maximum acceleration of 0.07545 m/s². The force acting on a passenger is expressed as F = 0.07545M, where M is the mass of the passenger. However, without a specific mass value, a numerical force cannot be determined, although the correct answer is noted as 976 Newtons based on the context provided.

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1) An airplane caught in a storm, is forced into a vertical periodic motion of period 30.2 seconds and amplitude 17.1 meters. The maximum force (in Newtons) acting on a passenger of mass {M} kG is?

T=2pi/[sqrt of (max a*gravity)/A)] ---> max a = 0.07545 m/s^2 and F=ma but the mass of the passenger is not given. Can someone please help? Thanks.
 
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buffgilville said:
F=ma but the mass of the passenger is not given. Can someone please help? Thanks.

It looks to me like your answer is supposed to be in terms of M.
 
If the answer is in terms of m than the force is 0.07545M, where M=mass, right? but the correct answer is 976 Newtons.
 
buffgilville said:
If the answer is in terms of m than the force is 0.07545M, where M=mass, right?

Right, but there doesn't seem to be enough information to get a single numerical value for the force. You can do an analysis on an individual passenger (Since you were asked for the force "on a passenger", I'm taking it to mean that you are looking for the normal force N):

N-mg=ma
N=mg+ma

so...

Nmax=mg+mamax.

Then you can do an analysis on the airplane. I model it as a mass on a spring.

kx-Mg=Ma
(4π2M/T2)x-Mg=Ma

so...

amax=(4π2/T2)xmax

You can substitute that expression for amax into the equation for Nmax, but without knowing the mass m of the passenger you can't get a numerical result.
 
I don't get it either. There must be a way to find the force... :cry:
 

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