HELP Pressure Change for equation without volume

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SUMMARY

The discussion focuses on calculating the total pressure in a tank containing nitrogen (N2) and hydrogen (H2) gases after ammonia (NH3) formation, without needing to know the volume or number of moles. The reaction equation is N2 + 3H2 → 2NH3, with initial pressures of 5.0 atm for N2 and 10.0 atm for H2. The final partial pressure of NH3 is given as 3.2 atm, leading to a total pressure calculation of 15 - 2x, where x represents the extent of the reaction.

PREREQUISITES
  • Understanding of gas laws, specifically the ideal gas law (PV=nRT).
  • Knowledge of chemical reaction stoichiometry.
  • Familiarity with partial pressures and Dalton's Law of Partial Pressures.
  • Basic algebra for solving equations.
NEXT STEPS
  • Study the ideal gas law and its applications in chemical reactions.
  • Learn about Dalton's Law of Partial Pressures and its implications in gas mixtures.
  • Explore stoichiometry in chemical reactions, focusing on limiting reactants and reaction yields.
  • Practice solving problems involving gas reactions and pressure changes without volume data.
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Chemistry students, chemical engineers, and anyone involved in gas reaction calculations or thermodynamics will benefit from this discussion.

Navygal
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HELP! Pressure Change for equation without volume

Homework Statement



A tank is pressurized with 5.0 atm of N2 and 10.0 atm of H2. Ammonia (NH3) is formed. When the pressure finally remains constant, indicating that the reaction has proceeded as far as it will go, the partial pressure of ammonia is 3.2 atm. What is the total pressure in the tank assuming that neither the temperature nor the volume of the container have changed?

Homework Equations



PV=nRT??

The Attempt at a Solution



I don't know how to go about this without using volume or number of moles. Is there another equation I should use??
Any help would be greatly appreciated
 
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Assume the tank has volume V. You will see that the V cancels out in the end. (alternatively if you like using numbers instead of variables, just use an arbitrary volume like 1L, plug in the numbers and see what the answer is).
 


I agree with Ygg.. Assume volume and temperature are the same at beginning and end. Then the pressure is proportional to moles. The equation is N2+3H2 -> 2NH3. Assume this has an extent of x (x moles of N2 reacted). Starting moles N2=5, H2=10. Ending moles N2=5-x, H2=10-3x, NH3=2x. Total pressure at end = sum of three partials = 15-2x.
The problem gives you NH3= 3.2 atm at end = 2x. Total pressure at end= you solve it.
 

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