Help regarding a question Parseval's Theorem

In summary: Yes, this is a Fourier series. The a_n values represent frequencies of the cosine and sine parts of the series, respectively.
  • #1
TFM
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Homework Statement



The Fourier series for f(x) = x2 over the interval (−1/2, 1/2) is:

[tex] f(x) = \frac{1}{12}-\frac{1}{\pi^2} (cos 2\pi x - \frac{1}{2^2}cos4\pi x + \frac{1}{3^2}cos6\pi x) ... [/tex]

Using Parseval's Theorem, show that

[tex] \sum _{n = 1}^\infty \frac{1}{n^4} = \frac{\pi^4}{90} [/tex]

Homework Equations



Fourier's Series:

[tex] f(x) = \frac{1}{2}a_0 + \sum _{n = 1}^\infty a_n cos\frac{2\pi nx}{l} \sum _{n = 1}^\infty b_n sin \frac{2\pi nx}{l}[/tex]

[tex] a_0 = \frac{1}{l} \int^{\frac{l}{2}}_{\frac{-l}{2}}f(x) dx [/tex]

[tex] a_n = \frac{1}{l} \int^{\frac{l}{2}}_{\frac{-l}{2}}f(x) cos \frac{2\pi nx}{l} dx [/tex]


[tex] b_n = \frac{1}{l} \int^{\frac{l}{2}}_{\frac{-l}{2}}f(x) sin \frac{2\pi nx}{l} dx [/tex]

Parseval's Theorem:

[tex] \frac{1}{2\pi} \int^{\pi}_{-\pi}f(x)^2 dx = \frac{1}{4}a_0^2 + \frac{1}{2} \sum _{n = 1}^\infty a_n^2 + \frac{1}{2}\sum _{n = 1}^\infty b_n^2 [/tex]

The Attempt at a Solution



See I'm not quite sure where to go from here. It says that it is a Fourier series, but it doesn't seem to fit with the definition of Fourier Series I have quoted below?

Any assitance would be greatly appreciated,

TFM
 
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  • #2
You multiplied the cosine and sine portions of the Fourier series together, they're supposed to be added. At any rate

For your f(x), a0=1/6 and then you can distribute the [tex]\frac{-1}{\pi^2}[/tex] to calculate the other ai's

And then the sine component is just all zeroes (so all your bi's will be 0)
 
  • #3
So firstly,

[tex] f(x) = \frac{1}{2}a_0 + \sum _{n = 1}^\infty a_n cos\frac{2\pi nx}{l} + \sum _{n = 1}^\infty b_n sin \frac{2\pi nx}{l} [/tex]

And

[tex] a_0 = \frac{1}{6} [/tex]

As there are no sins, this implies that b_n = 0 (since b_n is the sin component.)
Multiplying out the brackets:

[tex] f(x) = \frac{1}{12} - (\frac{1}{\pi^2}cos 2\pi x - \frac{1}{\pi^2}\frac{1}{2^2}cos4\pi x + \frac{1}{\pi^2}\frac{1}{3^2}cos6\pi x ...) [/tex]

[tex] f(x) = \frac{1}{12} - (\frac{1}{\pi^2}cos 2\pi x - \frac{1}{4\pi^2}cos4\pi x + \frac{1}{9\pi^2}cos6\pi x ...) [/tex]

So the a_n seems to be an increasing value:

[tex] a_n = frac{1}{\pi^2}, frac{1}{4\pi^2}, frac{1}{9\pi^2}... [/tex]

Does this seem okay so far?

?

TFM
 

1. What is Parseval's Theorem?

Parseval's Theorem is a mathematical theorem that relates the energy of a function in the time domain to its energy in the frequency domain. It states that the sum of the squared magnitudes of the Fourier coefficients of a function is equal to the integral of the squared function itself.

2. How is Parseval's Theorem used in science?

Parseval's Theorem is used in various fields of science, such as signal processing, acoustics, and quantum mechanics. It allows scientists to analyze the energy of a function in both the time and frequency domains, making it useful in understanding the behavior of physical systems and signals.

3. What are the applications of Parseval's Theorem?

Some common applications of Parseval's Theorem include analyzing the sound spectrum of musical instruments, calculating the power distribution in electrical circuits, and determining the energy distribution in quantum mechanical systems.

4. Can Parseval's Theorem be applied to all types of functions?

Yes, Parseval's Theorem can be applied to any function that satisfies certain conditions, such as being square-integrable and having a finite energy. This includes many common functions used in science and engineering.

5. How is Parseval's Theorem related to the Fourier Transform?

Parseval's Theorem is closely related to the Fourier Transform, which is a mathematical tool used to decompose a function into its frequency components. The theorem states that the energy of a function in the time domain is equal to the energy of its Fourier transform in the frequency domain.

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