Help Setting up an Equation to use the Elimination Method

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SUMMARY

The discussion focuses on solving the initial value problem (IVP) defined by the equations x' = 2x + y - e^(2t) and y' = x + 2y, with initial conditions x(0) = 1 and y(0) = -1. The user initially struggles with eliminating the variable y to simplify the equations for solving x. After several attempts, they discover that multiplying the first equation by D and the second by (D-2) simplifies the problem significantly, leading to a clearer path for finding the solution.

PREREQUISITES
  • Understanding of initial value problems (IVP) in differential equations
  • Familiarity with the derivative operator D in the context of differential equations
  • Knowledge of methods for eliminating variables in systems of equations
  • Experience with exponential functions and their derivatives
NEXT STEPS
  • Study the method of elimination in systems of differential equations
  • Learn about the application of the derivative operator D in solving differential equations
  • Explore techniques for solving initial value problems (IVP) in differential equations
  • Investigate the use of exponential functions in differential equations and their solutions
USEFUL FOR

Students studying differential equations, particularly those tackling initial value problems and seeking to improve their problem-solving techniques in mathematical analysis.

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Homework Statement



The question is to solve the IVP: x'=2x+y-e^2t & y'=x+2y, where x(0)=1, y(0)=-1

Homework Equations



Arranging the equations and substituting in D for the derivatives, the equations become:
1. (D-2)x-Dy= -2e^2t
2. (D-2)y-Dx= 0

The Attempt at a Solution



My first attempt was to eliminate the y variable and leave x to solve for. But, looking at the problem, I'm having an issue with figuring out how to set the equation up in order to do so. One attempt was to eliminate the (D-2)x & y on both equations:

(D-2)x-Dy=-2e^2t *(D-2)y
(D-2)y-Dx=0 *(D-2)x

(D-2)x(D-2)y-Dy(D-2)y=(D-2)-2e^2t
(D-2)x(D-2)y-Dx(D-2)x=0

Subtracting, this leaves:

Dx(D-2)x-Dy(D-2)y=0

This is far messier than we've dealt with in class, but not beyond the realm something the teacher might give us. I'm wondering if there's an easier way to clear out one of the terms in order to make the Diff Eq easy to solve for x. Once I get one value solved, I can go back and figure out the other. Just the set up is tricky. Thanks for any help you can provide!

EDIT: I was able to get some help. Multiply (1) by D and (2) by (D-2) and voila!
 
Last edited:
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Note that you wrote "y'=x+2y" as the second equation, and then proceeded to work with "2. (D-2)y-Dx= 0".
So somehow you have introduced a derivative operator on the x?
 

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