- #1

Pete69

- 8

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could anyone help me with solving this second order differential equation? I am a noob on here so not sure how you get the mathplayer stuff on... so the equation is of the form

x'' +ax' + bx^n = 0

(x^n means x to the power n, with a and b constants). i tried substituting x'=u to get a first order linear, but then got lost in the algebra of solving the linear DE with a integrating factor.. so is there a different method?

thanks, Pete

x'' +ax' + bx^n = 0

(x^n means x to the power n, with a and b constants). i tried substituting x'=u to get a first order linear, but then got lost in the algebra of solving the linear DE with a integrating factor.. so is there a different method?

thanks, Pete

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