Help understanding a relativity train

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    Relativity Train
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SUMMARY

This discussion centers on the principles of special relativity, particularly regarding the speed of light and relative motion. It clarifies that regardless of a train's speed, both a flashlight inside the train and one outside will emit light at the same speed, adhering to the constant speed of light. The conversation also addresses the misconception that running inside a fast-moving train could exceed the speed of light, explaining that special relativity dictates the combined speed will always remain below the speed of light. Additionally, it emphasizes that the energy required to run does not change based on the train's speed.

PREREQUISITES
  • Understanding of special relativity principles
  • Familiarity with the concept of the speed of light (c)
  • Basic knowledge of frame of reference in physics
  • Mathematical comprehension of relativistic velocity addition
NEXT STEPS
  • Study the Lorentz transformation equations
  • Explore the concept of time dilation in special relativity
  • Learn about relativistic mass and energy equivalence
  • Investigate the implications of light speed constancy on modern physics
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Students of physics, educators teaching relativity, and anyone interested in understanding the fundamental concepts of motion and light speed in the context of special relativity.

JH27
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Hi all,

I've read some references to an example of a person on a train using a flashligt and one outside the train also using a flashlight and as I understand it both flashes would travel at the same speed even if the train was moving?
Also as I understand nothing can travel faster then the speed of light?

But suppose then that you are on a train traveling just 20 km/h below the speed of light and then started running down the isle at 30 km/h wouldn't you go faster then the speed of light then?

...also as more energy is needed to accelerate closer to the speed of light, would you expell more energy(calories) running down a train that was moving fast than running at the same speed down a train that was moving slower since your combined speed would be closer to the speed of light?

Hope I am making any sense :biggrin: Just trying to wrap my head around this...
 
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From the runner's point of view (or frame of reference) it isn't they who are moving, but everything else. That means that YOU wouldn't feel any different than you normally did and everything you did would be normal. However, when you look at the outside world at that speed it is VERY different. Everything in your direction of travel is severely distorted and blue shifted, while everything behind you is severely redshifted.

Now from you're perspective on the train, everything in front is approaching you at 20 Km/h under the speed of light. If you ran down the isle at a local speed of 30, then you WOULDN'T see everything coming at you at 10 KM/H over the speed of light. Instead everything would distort slightly more and you would measure it still being under the speed of light, just a bit closer to c than it was, but still under it. If you somehow kept accelerating you would find that no matter how fast you tried to go, nothing would be coming at you at the speed of light. Each increase in you're velocity would net you a smaller and smaller actual increase in speed. Note that this is all from YOUR perspective. It's kind of complicated and i suggest you hit up wikipedia or do a google search and try to learn some basics of relativity.
 
JH27 said:
I've read some references to an example of a person on a train using a flashligt and one outside the train also using a flashlight and as I understand it both flashes would travel at the same speed even if the train was moving?
Also as I understand nothing can travel faster then the speed of light?
Both correct.

JH27 said:
But suppose then that you are on a train traveling just 20 km/h below the speed of light and then started running down the isle at 30 km/h wouldn't you go faster then the speed of light then?
No, if the speed of the train relative to the ground is u, and your speed relative to the train is v, special relativity says that your speed relative to the ground isn't u+v, but

[tex]\frac{u+v}{1+\frac{uv}{c^2}}[/tex]

Try it out with your numbers, and you'll see that it's less than c.

JH27 said:
...also as more energy is needed to accelerate closer to the speed of light, would you expell more energy(calories) running down a train that was moving fast than running at the same speed down a train that was moving slower since your combined speed would be closer to the speed of light?
No, the speed of the train is irrelevant for how hard it's going to be for you to run at a given speed relative to the train.

JH27 said:
Hope I am making any sense
The questions make sense, but they've been asked and answered many, many times before. You might want to look around and see if you find anything interesting in older threads.
 

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