Help Understanding Transposing Formula in Roarks Formulas for Stress and Strain

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Homework Statement



Hi, I'm looking through Roarks Formulas for Stress and Strain and I am having difficulty following one of the examples. Unfortunately my maths isn't as good as I would like. Hopefully someone can explain to me the steps taken to find the solution.

Homework Equations



The book states the following expression:

4.4661/n - 2(2.331)1/n + 1 = 0

From this it finds n = 2.86, unfortunately only the answer is given an no explanation. Can someone help?

Thanks
 
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There is no simple "algebraic" method to combine 4.4661/n and 2.3311/n so no simple "algebraic" method to solve that equation. You could do it graphically or using some numerical method such as Newton's method. And "2.86" is only an approximate solution, not exact.
 
Colnago said:

Homework Statement



Hi, I'm looking through Roarks Formulas for Stress and Strain and I am having difficulty following one of the examples. Unfortunately my maths isn't as good as I would like. Hopefully someone can explain to me the steps taken to find the solution.

Homework Equations



The book states the following expression:

4.4661/n - 2(2.331)1/n + 1 = 0

From this it finds n = 2.86, unfortunately only the answer is given an no explanation. Can someone help?

Thanks

For the solution of the problem *exactly as it is written*, Maple 14 gets n = 2.822595780, which rounds off to n ≈ 2.82 (NOT 2.86). If we assume, instead, that the equation should really by
[tex](67/15)^{1/n} - 2(7/3)^{1/n} + 1=0[/tex]
the solution becomes n = 2.795724837, which rounds off to n ≈ 2.80 (again, NOT 2.86).

Note: Maple uses numerical methods to solve such equations.