Help - Verify the Jacobi Identity (Arfken)

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Homework Help Overview

The discussion revolves around verifying the Jacobi Identity involving commutators in the context of matrix algebra. The original poster expresses confusion regarding the notation and the steps needed to prove the identity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the meaning of the notation, particularly the use of commas in the context of commutators. There are suggestions to expand both sides of the identity and to consider specific matrix forms for simplification. Some participants express uncertainty about the algebraic manipulation required due to the non-commutative nature of matrix multiplication.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and seeking further clarification. Some guidance has been offered regarding the expansion of terms, and there is an acknowledgment of the complexity involved in the algebraic proof.

Contextual Notes

Participants note the challenges posed by the non-commutativity of matrices and the potential for errors in expansion. There is a mention of previous attempts that were complicated by missing steps.

Fjolvar
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Hello, I'm unfamiliar with the notation used in this problem with the commas. I understand matricies, identities, etc. but not sure about the commas..

Question 3.2.9: Verify the Jacobi Identity: [A,[B,C]] = [B,[A,C]] - [C,[A,B]]

I see the BAC CAB rule here, but not sure how to show it. Any help on this problem would be greatly appreciated!
 

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The square brackets denote the commutator: [A,B] = AB-BA.
 
Any suggestions on setting this problem up to prove it? Just make 2x2 matricies with a1,a2,a3,a4 b1,b2,b3,b4.. etc? I haven't a clue.
 
Just expand both sides and show you end up with the same terms.
 
I know this should be easier than I'm making it. I tried to expand these in many ways but couldn't get it to work out. Since AB does not equal BA for example since we're dealing with matrices, I don't know how to prove this algebraically.. How do I expand this?
 
Post what you tried so we can see what you're doing.
 
Ok I attached what I have so far. In the first attempt I tried expanding everything out with matrices and then realized I actually left out a step in each part which would make things very messy so I thought there had to be an easier way, and in the second attempt I tried without using matrices but stopped because I'm not sure how to distribute since AB does not equal BA..
 

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Your final attempt is the way to go. All you have to do is finish off the righthand side.

You found, with sign corrections, that

[B,[A,C]]=BAC-BCA-ACB+CAB
[C,[A,B]]=CAB-CBA-ABC+BAC

so

[B,[A,C]]-[C,[A,B]] = (BAC-BCA-ACB+CAB)-(CAB-CBA-ABC+BAC)

Now just simplify it as some of the terms cancel, and you'll be left with what you have for (1).
 
Sometimes I think I just need more confidence in doing these problems. Thank you very much!
 

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