A bowling ball rolls off an angled roof. The roof is sloped downward at 18.4°, and the eaves are 12.0m above the ground.If it lands 2.0m away from the building how fast was it rolling when it left the roof(i.e find Vi).
I know I have to use the equation Vh=Δx/Δt. I then solved for Vi(which took me quite a while considering that Vi was on both sides of the equation and then I had to isolate it).
The Attempt at a Solution
This is the most complex problem I've ever seen as Vi was on both sides(was told by teacher to isolate radical to find Vi). I was eventually able to isolate Vi on one side and got the equation:
This equation looks really funky so I'm not sure if its right, I got an estimated value answer of 5m/s.
P.S For clarification on the equation, the g and Δx are both divided by the sin and cos.