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Help with 3 objects/masses connected by string over frictionless pulley?

  1. Oct 4, 2009 #1
    1. The problem statement, all variables and given/known data
    Three masses connected by light strings are shown in the figure below (I will try my best in describing the figure):
    There is light, frictionless pulley with two masses, M2 and M3, on the left and one mass, M1, on the right. They are all connected by light strings. Given m1 = 10 kg, m2 = 7.48 kg, m3 = 8.01 kg, and g = 9.8 m/s2. The acceleration of gravity is 9.8 m/s2 . Find the downward acceleration of m2 mass. answer in units of m/s^2


    2. Relevant equations
    SigmaF= ma
    mg=fg

    3. The attempt at a solution

    I drew three separate free body diagrams for each of the masses.
    For M1:
    Ft-MG=MA
    Ft-98=10a

    For M2:
    MG-Ft=MA
    7.48(9.8)-Ft=7.48a
    73.304-Ft=7.48a

    So I combined the two equations and got -1.413 m/s^2. I though because it is downward, I didn't need the negative, so I put in UT, 1.413, it was wrong, I also put -1.413, it was also wrong. Then I tried using M3 and combined the acceleration of M3 and M2, which was 8.387, which is also wrong. Then I read on another thread that you can use the equation:
    A= [(M1-M2)/(M1+M2)] * G. I got 1.413. I honestly don't know what to do at this point, can somebody please help me. Thanks in advance.
     
  2. jcsd
  3. Oct 4, 2009 #2
    Anybody? Please?
     
  4. Oct 4, 2009 #3
    If you could post the diagram that would help a lot so we would know where to start...
     
  5. Oct 4, 2009 #4
    Diagram posted. It is on the last page, number 018 (part 1of 3).
     

    Attached Files:

  6. Oct 4, 2009 #5
    Please can anybody help? I even posted the diagram.
     
  7. Oct 4, 2009 #6
    Nevermind, figured it out.
     
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