Help with a differential equation

Click For Summary
SUMMARY

The discussion focuses on solving the one-dimensional differential equation -d/dx [a(x) du/dx] = p(x) with boundary conditions u(0) = 0 and u(1) = 0, where a(x) = 1 and p(x) = 1. The general solution approach involves integrating the equation, leading to the expression u(x) = -∫_x^1 (1/a(u)) ∫_0^u p(t) dt du. Given the specific functions for a(x) and p(x), the problem simplifies to solving the second-order equation d²u/dx² = -1, which can be resolved through two straightforward integrations.

PREREQUISITES
  • Understanding of differential equations, particularly second-order linear equations.
  • Familiarity with boundary value problems and their solutions.
  • Knowledge of integration techniques in calculus.
  • Ability to manipulate and apply specific functions in differential equations.
NEXT STEPS
  • Study the method of solving second-order linear differential equations.
  • Learn about boundary value problems and their significance in physics and engineering.
  • Explore integration techniques, particularly double integrals in the context of differential equations.
  • Investigate the implications of varying coefficients in differential equations compared to constant coefficients.
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are dealing with differential equations, particularly those interested in boundary value problems and integration techniques.

ElvenVeil
Messages
1
Reaction score
0

Homework Statement



Hello

I am new to this forum, but I hope I can get help with a problem I haven't been able to figure out what to do with.

info:

we have a one dimensional equation -d/dx [a(x) du/dx] = p(x)

where we seek a solution u(x) where x is within [0,1] , that satisfies the 2 boundary conditions u(0) = 0, u(1) = 0

p and a is given by a(x) = 1 and p(x) = 1

any help with this problem would be very nice. On beforehand thanks


Homework Equations





The Attempt at a Solution



My thought was to first find a general solution to the equation and then insert the conditions given. I have a hard time finding a general solution to the equation (-d/dx [a(x) du/dx] = p(x) ) so I feel a little stuck on how to approach it.
 
Physics news on Phys.org
ElvenVeil said:
p and a is given by a(x) = 1 and p(x) = 1
Erm...just use this? I don't think it is possible to obtain a closed form expression for the general solution for arbitrary a(x) and p(x).
 
The general solution is very difficult- although I think it can be done in terms of
[tex]u(x)= -\int_x^1\frac{1}{a(u)}\int_0^u p(t)dt du[/tex]

But you are give that a(x)= 1 and p(x)= 1 so the problem is to solve [itex]\frac{d^2x}{dt^2}= -1[/itex] which can be done by two simple integrations.
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
4K
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
2K