Cacophony
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Homework Statement
How do I solve this equation?
lim x>0 (x^3 - 2x^2 + x)/tanx
I don't know what to do here, please help. Thank you
The limit equation lim x>0 (x^3 - 2x^2 + x)/tan(x) can be solved using L'Hôpital's rule. This rule applies when evaluating limits that result in indeterminate forms such as 0/0. By differentiating the numerator and denominator separately, the limit can be simplified and evaluated effectively. The discussion emphasizes the importance of recognizing when to apply L'Hôpital's rule in calculus problems.
PREREQUISITESStudents studying calculus, particularly those tackling limit problems, and educators looking for teaching resources on L'Hôpital's rule and limit evaluation techniques.
Cacophony said:Homework Statement
How do I solve this equation?
lim x>0 (x^3 - 2x^2 + x)/tanx
I don't know what to do here, please help. Thank you