Help with a mechanical lagrangian problem

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SUMMARY

The discussion focuses on solving a mechanical Lagrangian problem defined by the Lagrangian L = 1/2mv² - mgz. The primary tasks include deriving the equations of motion using the Euler-Lagrange equation, determining the position and velocity of a ball thrown upwards at time τ when it returns to the ground, and calculating the action S. The user correctly identifies that the force acting on the ball is F = -dp/dt, leading to acceleration a = -g, and attempts to express the position and velocity equations, although they encounter difficulties in applying the constraints related to z(τ) = 0.

PREREQUISITES
  • Understanding of Lagrangian mechanics and the Euler-Lagrange equation.
  • Familiarity with the concepts of action and integrals in classical mechanics.
  • Basic knowledge of kinematics, particularly motion under constant acceleration.
  • Ability to manipulate vector equations and apply initial conditions in physics problems.
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  • Learn how to calculate the action S for different Lagrangians in classical mechanics.
  • Explore kinematic equations for projectile motion, focusing on vertical motion under gravity.
  • Investigate the implications of initial conditions on the motion of objects in Lagrangian mechanics.
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black_hole
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Homework Statement



We are given L = 1/2mv2 - mgz.

a) Find the equations of motion.
b) Take x(0) [vector] = 0; v(0) [vector] = v0 [vector] ; v0z > 0 and find x(τ) [vector] and v(τ) [vector], such that z(τ) = 0;  τ≠0.
c) Find S.

Homework Equations



Euler-Lagrange equation and definition of action.

The Attempt at a Solution



a) Using the Euler-Lagrange equation:

∂L/∂x - d/dt(∂L/∂v) = 0
-mg - d/dt(mv) = 0
-mg = d/dt(mv)
F = -dp/dt

b) If F = -dp/dt, then a = -g. So;

v = -vt + v0 and x = -1/2gt2 + v0t

Hmmm, that's where I'm stuck; I'm not sure how to implement the last two constraints. Maybe if z(τ) = 0 but τ≠0 then z = 1/2gt2 - vozt = 0 when t = (z * v0z)/g = τ ?
(I'm not explicitly given v0z...)

c) S = ∫Ldt = 1/2m∫v2dt - mg∫zdt

If my above expressions for v and z are correct then I presume I can use those tot find the integrals...?


 
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Hi black_hole! :smile:

You seem to be mixing up x and z.

This is a ball being thrown up (v0z > 0).
They want to know when the ball is back on the ground...
Or rather where the ball is at that time and what its velocity is as a function of its initial velocity v0.
 

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