Help with a pulley problem with 3 masses

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
31 replies · 4K views
haruspex said:
It seems each acceleration is being taken as positive in the likely direction of movement: 1 to the right, 2 to the left, 3 down.
For each unit of distance 1 advances, 3 drops 1 unit.
For each unit 2 advances, 3 drops 2 units.
Thanks @haruspex but I still don't understand
if "For each unit of distance 1 advances, 3 drops 1 unit" this means that ##|\vec{a_1}|=|\vec{a_3}|## right?
Also I don't understand how the following holds:
"For each unit 2 advances, 3 drops 2 units"
 
on Phys.org
Delta2 said:
Thanks @haruspex but I still don't understand
if "For each unit of distance 1 advances, 3 drops 1 unit" this means that ##|\vec{a_1}|=|\vec{a_3}|## right?
Only if 2 stays put. Similarly, 3 dropping 2 for each unit 2 moves is on the assumption that 1 stays put.
So in algebra it's ##\frac{\partial a_3}{\partial a_1}=1## etc.
 
  • Like
Likes   Reactions: Delta2