Help with a troublesome integral

  • Context: Graduate 
  • Thread starter Thread starter mmzaj
  • Start date Start date
  • Tags Tags
    Integral
Click For Summary
SUMMARY

The integral discussed is defined as I(s)=∫₀ⁿ log(1+(s²/4π²) log²(1+ix)) e⁻²πnx dx, where s is a complex parameter and n is a positive integer. The user attempted to simplify the integral by substituting log(1+ix) with y, leading to I(s)=-i∫ₗ log(1+(s²/4π²)y²) exp(2πin e^y) e^y dy, necessitating a defined path for integration. The discussion highlights the importance of addressing the complex logarithm's real and imaginary components for further simplification.

PREREQUISITES
  • Understanding of complex analysis, particularly complex logarithms
  • Familiarity with integral calculus and improper integrals
  • Knowledge of substitution methods in integration
  • Experience with exponential functions and their properties
NEXT STEPS
  • Study the properties of complex logarithms in detail
  • Learn about contour integration techniques in complex analysis
  • Research methods for evaluating improper integrals
  • Explore the application of the residue theorem in complex integrals
USEFUL FOR

Mathematicians, physicists, and students engaged in advanced calculus or complex analysis, particularly those working with integrals involving complex parameters.

mmzaj
Messages
107
Reaction score
0
We have the integral:
[tex]I(s)=\int_{0}^{\infty}\log\left(1+\frac{s^{2}}{4\pi^{2}} \log^{2}(1+ix)\right ) e^{-2\pi nx}dx[/tex]
Where [itex]s[/itex] is a complex parameter, and [itex]n[/itex] is a positive integer.
Things i tried:
Set [itex]\log(1+ix)=y[/itex], so that
[tex]I(s)=-i\int_{c}\log\left(1+\frac{s^{2}}{4\pi^{2}}y^{2} \right )\exp\left(2\pi in e^{y} \right )e^{y}dy[/tex]
Where the path [itex]c[/itex] has to be defined !
 
Physics news on Phys.org

Similar threads

  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K