A 3.00-liter aluminum cylinder at 5.00°C is filled to the brim with gasoline at the same temperature. If the aluminum and gasoline are warmed to 53.0°C, how much gasoline spills out? [Hint: Be sure to account for the expansion of the container. Also, ignore the possibility of evaporation, and assume the volume coefficients are good to three digits.
Coeff of Linear Expansion for Al : 24 X 10^-6
Coeff of Volume Expansion for gasoline: 9.6 X 10 ^-4
Volume Expansion Formula: ΔV = βVoΔT
The Attempt at a Solution
I calculated the volume expansion formula for each variable and came up this:
aluminum = (24 X 10^-6)(3.00L)(53.0 - 5.00)°C = .003456
gasoline = (9.6 X 10^-4)(3.00L)(53.0 - 5.00)°C = .13824
I then subtracted (.13824) - (.003456) = .134784 = .135
And this is the incorrect answer.... The correct answer is 128 cm^3 so I don't know what I am doing incorrectly....