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## Homework Statement

A 3.00-liter aluminum cylinder at 5.00°C is filled to the brim with gasoline at the same temperature. If the aluminum and gasoline are warmed to 53.0°C, how much gasoline spills out? [Hint: Be sure to account for the expansion of the container. Also, ignore the possibility of evaporation, and assume the volume coefficients are good to three digits.

## Homework Equations

Coeff of Linear Expansion for Al : 24 X 10^-6

Coeff of Volume Expansion for gasoline: 9.6 X 10 ^-4

Volume Expansion Formula: ΔV = βVoΔT

## The Attempt at a Solution

I calculated the volume expansion formula for each variable and came up this:

aluminum = (24 X 10^-6)(3.00L)(53.0 - 5.00)°C = .003456

gasoline = (9.6 X 10^-4)(3.00L)(53.0 - 5.00)°C = .13824

I then subtracted (.13824) - (.003456) = .134784 = .135

And this is the incorrect answer.... The correct answer is 128 cm^3 so I don't know what I am doing incorrectly....