(adsbygoogle = window.adsbygoogle || []).push({}); An 8000kg aluminum flagpole 100m long is heated by the sun from a temperature of 10°C to 20°C. Find the work done (in J) by the aluminum if the linear expansion coefficient is 24*10^{-6}/°C. (The density of aluminum is 2.7*10^{3}kg/m^{3}and 1 atm = 1.0*10^{5}N/m^{2})

I know w=PΔV, and I know V at 10°C = mass/density= 8000/2.7*10^{3}= 2.963m^{3}

I know how much longer the flagpole grows: ΔL=αLΔT = 24*10^{-6}(100)(20-10)=0.024m

But how does the volume at 20°C relate to the growth of the flagpole through linear expansion?

The answer is suppsoed to be 213 J.

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# Homework Help: Work done through linear expansion

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