# Help with continous line graph (interval notation)

• Torshi
But the main issue was that the site didn't recognize my right answer due to a simple bracket issue. In summary, the problem was to write the domain of a function in interval notation, but there was confusion due to the wording of the question and a bracket issue on the website. The correct answer is [-2,-1)U(-1,0)U(0,1)U(1,4].
Torshi

## Homework Statement

See attachment: what is the interval notation of the continuous line

no equation

## The Attempt at a Solution

(-2,-1)U(-1,inf) ? not sure then it goes to 1 then to -inf? There are two continuous lines
(-2,-1)U(-1,1)U(1,inf)? No...
i feel like an idiot on this problem

#### Attachments

• 7c93a0372edb3d4679891d4f3efb1bf8-4567-sethomework_02prob1image1.png
1.9 KB · Views: 366
Last edited:
Torshi said:

## Homework Statement

See attachment: what is the interval notation of the continuous line

no equation

## The Attempt at a Solution

(-2,-1)U(-1,inf) ? not sure then it goes to 1 then to -inf? There are two continuous lines
(-2,-1)U(-1,1)U(1,inf)? No...
i feel like an idiot on this problem
What is the function's value at x = 0 ?

SammyS said:
What is the function's value at x = 0 ?

idk inf?

Torshi said:
idk inf?
∞ is not a permissible value for a function.

Is the function even defined at x = 0 ?

SammyS said:
∞ is not a permissible value for a function.

Is the function even defined at x = 0 ?

Sorry and no it's not I believe. Nothings there. From -1 there is discontinuity and a jump to 1

Last edited:
I'm really having trouble with this problem

Last edited:
Torshi said:
bump

Read the Forum rules regarding bumping.

Torshi said:
Sorry and no it's not I believe. Nothings there. From -1 there is discontinuity and a jump to 1
The function is not defined at x=0, so how can it be continuous there? (You said it was continuous on (-1,1) . )

SammyS said:
The function is not defined at x=0, so how can it be continuous there? (You said it was continuous on (-1,1) . )

I'm stuck after (-2,-1) if that's even right for the first continuous line

So there is a hole after -1. Then there is jump to 1 so that (-1,1) doesn't apply since at 0 it's undefined. So from 1 onto where? at 1 there are 2 holes, one going infinitely down and another that goes right

Not continuous:
1.) not defined
2.) limit DNE
3.) limit does not equal to evaluation --> is this the problem? this last one

(-2,-1)U(-1,0)U(0,1)U(1,3)U(3,4) ? Nope.. How do I do this?

Last edited:
Torshi said:
I'm stuck after (-2,-1) if that's even right for the first continuous line

So there is a hole after -1. Then there is jump to 1 so that (-1,1) doesn't apply since at 0 it's undefined. So from 1 onto where? at 1 there are 2 holes, one going infinitely down and another that goes right

Not continuous:
1.) not defined
2.) limit DNE
3.) limit does not equal to evaluation --> is this the problem? this last one
What do you mean by "continuous line" ? You're looking for continuity over a set of intervals.

Torshi said:
(-2,-1)U(-1,0)U(0,1)U(1,3)U(3,4) ? Nope.. How do I do this?
Why do you say the graph is not continuous at x=3 ? (Which of the three above reasons?)

I know the answer finally. The problem was that I had it all along, but everytime I typed it into the box online it would not recognize it due to simple [] in which that's why I was so confused...

-Thanks

SammyS said:
What do you mean by "continuous line" ? You're looking for continuity over a set of intervals.

Why do you say the graph is not continuous at x=3 ? (Which of the three above reasons?)

(1,4]

The previous answers I was posting was simply out of confusion since I've typed in the right answer before and was marked as incorrect, hence my confusion.

Thank you

Torshi said:

## Homework Statement

See attachment: what is the interval notation of the continuous line

no equation

## The Attempt at a Solution

(-2,-1)U(-1,inf) ? not sure then it goes to 1 then to -inf? There are two continuous lines
(-2,-1)U(-1,1)U(1,inf)? No...
i feel like an idiot on this problem

I'm not sure that the people who replied in this thread even understood what the problem is. "Interval notation of the continuous line" makes no sense whatsoever.

Were you supposed to write interval notation for the graph you attached?

Yes, writing the continuous line in interval notation. Which if done right you can identify the jumps or moments of discontinuity.

Torshi said:
Yes, writing the continuous line in interval notation.
That's not what I said. The goal of the exercise, I believe, was to write the domain of the function in interval notation.
Torshi said:
Which if done right you can identify the jumps or moments of discontinuity.

Mark44 said:
That's not what I said. The goal of the exercise, I believe, was to write the domain of the function in interval notation.

Yes, but it didn't state that specifically in the problem. It simply just said write in interval notation of the continuous line and if there is more then one interval use a union sign. It's fine now though, I figured out the answer and the main reason why I couldn't figure it out was because the site wanted a bracket at the beginning and end, simple mistake which confused me into thinking one of the right answers I plugged in didn't work. I believe the other users knew what my question was because they were guiding me in the right direction.

## 1. How do I read a continuous line graph?

A continuous line graph represents data that changes over time or another continuous interval. The x-axis usually represents time or another continuous variable, while the y-axis represents the corresponding data values. The graph is read by following the line and identifying the data point at a specific time or interval.

## 2. How do I create a continuous line graph?

To create a continuous line graph, you first need to have data points for the variable you want to graph. Then, plot the points on a coordinate plane and connect them with a line. Make sure the x-axis represents the continuous variable and the y-axis represents the corresponding data values. Label the axes and add a title to the graph for clarity.

## 3. What is the purpose of using interval notation in a continuous line graph?

Interval notation is a compact and efficient way to represent a range of values in a continuous line graph. It allows you to specify the starting and ending points of an interval using brackets and parentheses. This notation is commonly used to represent the domain and range of a function in mathematical notation.

## 4. How do I interpret intervals in a continuous line graph?

In a continuous line graph, intervals are represented as horizontal lines on the graph. They indicate a range of values along the x-axis. To interpret intervals, you need to look at the data points on the graph and determine the values that fall within the specified interval.

## 5. How can I use a continuous line graph for analysis?

A continuous line graph can be a useful tool for data analysis as it allows you to visualize trends and patterns over time or a continuous interval. By analyzing the slope of the line, you can determine if the data is increasing, decreasing, or staying constant. You can also compare multiple lines on the same graph to identify any relationships or correlations between the data.

• Calculus and Beyond Homework Help
Replies
10
Views
989
• Calculus and Beyond Homework Help
Replies
2
Views
998
• Calculus and Beyond Homework Help
Replies
4
Views
1K
• Calculus and Beyond Homework Help
Replies
3
Views
1K
• Calculus and Beyond Homework Help
Replies
9
Views
2K
• Calculus and Beyond Homework Help
Replies
32
Views
2K
• Calculus and Beyond Homework Help
Replies
1
Views
3K
• Calculus and Beyond Homework Help
Replies
2
Views
838
• Calculus and Beyond Homework Help
Replies
4
Views
1K
• Calculus and Beyond Homework Help
Replies
3
Views
437