Help with decelleration, acceleration and time

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SUMMARY

The discussion focuses on calculating time separation between two trains using the kinematic equation v² - u² = 2as, where u represents initial velocity, v is final velocity, s denotes displacement, and a indicates acceleration. By applying this formula, users can determine the displacement (s) and subsequently calculate the time (t) taken for the trains to pass a station. The scenario illustrates the practical application of these calculations in real-world train operations.

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  • Familiarity with concepts of velocity and acceleration
  • Basic knowledge of displacement in physics
  • Ability to solve algebraic equations
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Physics students, transportation engineers, and anyone interested in the dynamics of motion and time calculations in train operations.

djszkoda
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delete please.
 
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Hi, welcome to PF.

You need to use [tex]v^{2}-u^{2}=2as[/tex] where u is the initial velocity, v the final, s is the displacement and a is the acceleration. From this you can find s and then find t.
 
You have everything you need.

Imagine two trains running together on parallel tracks. One slows down, stops for a while and then accelerates back to cruising speed. The other one is now a good way ahead. What you have to find is the time separation between these two trains as they pass through the next station without stopping.
 

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