Help with describing a sequence

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Homework Help Overview

The discussion revolves around describing the sequence 0.3, 0.33, 0.333, 0.3333, 0.33333,... Participants are exploring the nature of this sequence and its convergence properties.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to express the sequence in terms of a formula for the nth term. Some are considering the relationship to geometric series and convergence to 1/3. Others are analyzing the differences between the terms and 1/3.

Discussion Status

There is an ongoing exploration of different interpretations of the sequence. Some participants have provided hints and guidance regarding the description of the sequence and its convergence, while others are questioning the assumptions made in the calculations.

Contextual Notes

Participants note that the original question specifically asks for a description of the sequence, which has led to some confusion regarding the focus of the discussion. There are also references to the constraints of summing series and the conditions under which certain formulas apply.

rock.freak667
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Homework Statement



Describe the following sequence

0.3,0.33,0.333,0.3333,0.33333,...


Homework Equations





The Attempt at a Solution



I tried to put the sequence as

[tex]\frac{3}{10},\frac{3}{10}+\frac{3}{100},\frac{3}{10}+\frac{3}{100}+\frac{3}{1000}+...[/tex]

But I didn't see anything happening there. Also I would hope the answer is convergent to [itex]\frac{1}{3}[/itex] since it looks like the number of 3's tend to infinity which would be the number of 3's in [itex]\frac{1}{3}[/itex]
 
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It's 3 times the geometric series (1/10)^n starting at n=1, isn't it? The series sums to 1/9, doesn't it?
 
.3,.33,.333,.3333...
> 3 [.1+.11+.111+.1111...]
Solve in factors of 10 now ...
go ahead...
 
rock.freak667 said:
Describe the following sequence

0.3,0.33,0.333,0.3333,0.33333,...

Hi rock.freak667! :smile:

You're only asked to describe the sequence.

In other words: find a formula A_n for the nth term.

For example, if the sequence is 1 8 27 64 …, then you describe it as {n³}.

Hint: As you point out, they're obviously getting closer to 1/3. So what is the difference between each term and 1/3? :smile:
 
tiny-tim said:
Hi rock.freak667! :smile:

You're only asked to describe the sequence.

In other words: find a formula A_n for the nth term.

For example, if the sequence is 1 8 27 64 …, then you describe it as {n³}.

Hint: As you point out, they're obviously getting closer to 1/3. So what is the difference between each term and 1/3? :smile:

well the differences are like this

1/3-0.3=0.0333...
1/3-0.33=0.00333...
1/3-0.333=0.000333...

So the differences run in a GP of first term a=0.0333... and common ratio r=0.1

But the sum to infinity = 0.0333../0.9 = 0.333...*1/9 = 1/3 * 1/9 = 1/27..Not 1/3 as I wanted.
 
rock.freak667 remember that [tex]\sum\frac{1}{10^{n}} = \frac{1}{1-\frac{1}{10}}[/tex] only when n goes from 0 to infinity. Is that the case in your example?
 
rock.freak667 said:
well the differences are like this

1/3-0.3=0.0333...
1/3-0.33=0.00333...
1/3-0.333=0.000333...

Hi rock.freak667! :smile:

(remember, the question asks you to describe the sequence, and you haven't specifically done that yet.)

So 3An = 1 - what ?

And so ∑An = … ? :smile:
 

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