Help with Displacement ( Vectors)

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Homework Help Overview

The discussion revolves around a problem involving displacement and vector components, specifically related to a hiker's journey described using directional angles. The subject area is primarily focused on vector analysis in physics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the method of breaking down the hiker's movements into X and Y components, questioning the use of positive and negative signs in their calculations. There is an emphasis on understanding the directional notation used in the problem.

Discussion Status

Some participants have offered guidance on how to interpret the directional angles and maintain consistency in sign usage. There is ongoing exploration of the correct approach to calculating the components, with multiple interpretations of the notation being discussed.

Contextual Notes

Participants mention the presence of an answer key, which has led to confusion regarding the calculations. There is a note about the potential differences in conventions used in various coursework, which may affect understanding.

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Homework Statement


A Hiker travels in the following directions
i) 3.2 Km ( N 42 W)
ii) 2.1 Km ( W 12 S )
iii) 1.9 Km ( E 62 N)

A) what is the resulting displacement?

Homework Equations


The Attempt at a Solution


A)
X Dir

3.2 sin 42 = 2.14
2.1 cos 12 = 2.05
1.9 cos 62 = .89
total = .94 <<<<<, Total is wrong :(
Y Dir

3.2 Cos 42 = 2.38
2.1 sin 12 = .44
1.9 sin 62 = 1.68
.26 <<< Total is wrong too

Can anyone explain on the X and Y Directions, Like where to Use positive and Negative Sign. I really Need help with this :P Beacuse it confuses me that were should i use the signs other than that rest is perfect.

Thanks for the help In Advance ^.^
 
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Welcome to PF.

The way I do it is draw a diagram.

I set N as positive Y and East as positive X.

Then I use that to keep track of the sign.

The N 42 W I read in quadrant notation in this regime then as +Y, -X with the angle made with the vertical Y axis.

Fwiw, I think quadrant notation usually uses just N or S followed by angle or direction E or W. For some reason this problem is using E and W as well, but I still read it as Direction - angle - direction off that direction.
 
I would assume that the problem is using this convention as well, unless you have previous experience with the conventions used in your course work.
 
thanks for the help, but ... i used it like u said still wrong... I have the answer key with me so yeah here's the problem aagain :

3.2 sin 42 = +2.14
2.1 cos 12 = -2.05
1.9 cos 62 = +.89
total = .94 <<<<<, Total is wrong :(
Y Dir

3.2 Cos 42 = - 2.38
2.1 sin 12 = -.44
1.9 sin 62 = +1.68
.26 <<< Total is wrong tooHEre's the Answer key i have it with me :P

3.2 sin 42 = +2.14
2.1 cos 12 = +2.05
1.9 cos 62 = -.89
total = 3.304
Y Dir

3.2 Cos 42 = + 2.38
2.1 sin 12 = - .44
1.9 sin 62 = +1.68
Total ==== 3.62

Meh can u Look again xD if u need more details i'll scan and post it on the web :P
 
It looks like that would be the problem.

When they say N 42 W, they are meaning 42 N of West

It seems they chose West as positive too.

Draw it out carefully, only reading it as:
North 42 degrees from West
West 12 degrees from South.
East 62 degrees from North.

I think that yields the right answer.

To answer your original question so long as you are consistent in staying with whatever sign you choose for your coordinates you should get to the same result.

However understanding their notation is also key.

Good Luck.
 
ok thanks :P btw my exam on physics is next week so i was having some trouble with that :P
 

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