Help With Forces: Determine Force Exerted by 3.2kg Block

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SUMMARY

The discussion centers on determining the force exerted by a 3.2 kg block on a 6.5 kg block when a 27 N force is applied. It is established that both blocks are in contact and sliding on a horizontal, frictionless surface. The correct interpretation is that the 3.2 kg block does exert a force on the 6.5 kg block due to the applied force acting on both blocks, which accelerates them together. The initial assumption that the 3.2 kg block exerts no force is incorrect; instead, the force exerted is a result of the combined acceleration of the blocks.

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  • Understanding Newton's Second Law of Motion
  • Basic concepts of force and acceleration
  • Knowledge of mass and weight relationships
  • Frictionless surface dynamics
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  • Calculate the acceleration of both blocks using F = ma
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Ok the problem is:
A 27-N force pushes a 6.5-kg block against a 3.2-kg block. If the blocks are sliding on a horizontal, frictionless surface, determine the force that the 3.2-kg block exerts on the 6.5-kg block.

I'm thinking that the 3.2 block's acceleration equals 0, and so the force would have to equal zero. Does this mean the 3.2 block exerts no force on the 6.5 block?
 
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potatosticks said:
Ok the problem is:
A 27-N force pushes a 6.5-kg block against a 3.2-kg block. If the blocks are sliding on a horizontal, frictionless surface, determine the force that the 3.2-kg block exerts on the 6.5-kg block.

I'm thinking that the 3.2 block's acceleration equals 0, and so the force would have to equal zero. Does this mean the 3.2 block exerts no force on the 6.5 block?
I think you are misreading the problem. The force of 27N pushes BOTH blocks along the table. The blocks are in contact with each other as they slide. Please try it again and report your results.
 

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