Help with Images and Optical Instrument Question

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SUMMARY

An object placed two focal lengths from a diverging lens produces a virtual image. The image distance (di) can be calculated using the lens formula, which states that for a diverging lens, the image distance will be less than the focal length (f). The magnification (M) is determined using the formula M = di/do, where do is the object distance, which in this case is 2f.

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  • Understanding of lens formulas, specifically for diverging lenses
  • Knowledge of virtual images and their characteristics
  • Familiarity with magnification calculations
  • Basic concepts of optics and focal lengths
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  • Study the lens formula for diverging lenses in detail
  • Learn how to calculate image distance (di) for different object placements
  • Explore magnification formulas and their applications in optics
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Jfhebb
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An object is placed two focal lengths from a diverging lens, (a) What kind of image forms? (b) What is the magnification? (c) Where is the image?

I am pretty sure the image is virtual, as for (b) and (c) I have no idea what to do.. Looking for some help, thanks in advance..


(a) I am pretty sure it is virtual
I am not sure what to do for b or c, I know we are looking for the Si for c, and as far as b goes I am not sure what magnification formula to use as we are given no values.
(b)
(c)
Thanks in advance,
 
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The object distance do is 2f, focal length is f. Find the image distance di using relevant equation. It should be less than f. Magnification = di/do
 

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