Resolution of Optical Instruments Question

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SUMMARY

The discussion focuses on solving a two-lens optical system problem involving a 3.1 cm tall object positioned 26 cm from a converging lens with a focal length of 13 cm, followed by a second lens with a focal length of 8.0 cm located 42 cm to the right of the first lens. The user applied the thin lens formula, 1/s + 1/s' = 1/f, and calculated the image distance for the first lens as s' = -8.67 cm. However, the user encountered difficulties in determining the correct image distance and height for the second lens, indicating potential errors in sign conventions or calculations.

PREREQUISITES
  • Understanding of the thin lens equation (1/s + 1/s' = 1/f)
  • Familiarity with magnification calculations (M = -s'/s)
  • Knowledge of ray diagrams for optical systems
  • Basic principles of image formation in lens systems
NEXT STEPS
  • Review the application of the thin lens equation with multiple lenses
  • Study sign conventions in optics to avoid calculation errors
  • Learn how to construct and interpret ray diagrams for complex lens systems
  • Explore the concept of combined magnification in multi-lens setups
USEFUL FOR

Students studying optics, physics educators, and anyone involved in optical instrument design or analysis.

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Homework Statement


A 3.1 cm--tall object is 26 cm to the left of a lens with a focal length of 13 cm. A second lens with a focal length of 8.0 cm is 42 cm to the right of the first lens.

Homework Equations


1/s + 1/s' =1/f
M=-s'/s and I'll have to multiply the two M's together to get the final M.

The Attempt at a Solution


I drew out a ray diagram. Maybe my signs are wrong?? 1/-26 + 1/s' = 1/13. s'=-8.67. This would be to the left of the first lens, so I tried doing 42+ s' and also 42-s' to use in the thin lens equation the second time (As the distance from lens 2), but none of my answers are working...?
 
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Calculate the distance between image and the second lens.
and Calculate the image height.
 

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