- #1

buttretler

- 8

- 0

## Homework Statement

I'm having trouble with this problem. I'm sapose to figure out at what angle a 5 kg block beings to slide with a static coefficient of 0.4.

**3. The Attempt at a Solution [/b**

So far I've been working it out through trigonometry and I've gotten that ... mu = mgcos(theta)/mgsin(theta) = cos/sin = tan(theta)

therefore that 0.4 =tan(theta)

(theta) = tan^-1(0.4)

(theta) = 21.8 degrees

so the box would slide at roughly 22 degrees.

I must of done something wrong but seems to make sense to me, theirs got to be more to it than this. can anyone help?

So far I've been working it out through trigonometry and I've gotten that ... mu = mgcos(theta)/mgsin(theta) = cos/sin = tan(theta)

therefore that 0.4 =tan(theta)

(theta) = tan^-1(0.4)

(theta) = 21.8 degrees

so the box would slide at roughly 22 degrees.

I must of done something wrong but seems to make sense to me, theirs got to be more to it than this. can anyone help?