Classical Mechanics - Statics - Mass and overhang

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SUMMARY

The discussion centers on a statics problem involving a block of mass M positioned under an overhang at an angle θ. The participants analyze the forces acting on the block, including normal and friction forces, and derive conditions for static equilibrium. It is established that the overhang angle θ must not exceed 45° for the block to remain static. Additionally, the relationship between the coefficient of friction µ and the angle θ is explored to determine the range of angles that maintain the block at rest.

PREREQUISITES
  • Understanding of free-body diagrams in classical mechanics.
  • Knowledge of static equilibrium conditions (ΣF_x = 0, ΣF_y = 0).
  • Familiarity with friction forces and coefficients (fs ≤ μsN).
  • Basic algebra for manipulating trigonometric functions and inequalities.
NEXT STEPS
  • Study the derivation of static equilibrium conditions in detail.
  • Learn about the implications of the coefficient of friction in static scenarios.
  • Explore the concept of free-body diagrams with more complex systems.
  • Investigate the effects of varying angles on static friction and equilibrium.
USEFUL FOR

Students and educators in physics, particularly those focusing on classical mechanics and statics, as well as engineers involved in structural analysis and design.

Lito
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Homework Statement



A block of mass M is positioned underneath an overhang that makes an angle θ > 0 with the vertical. You apply a horizontal force of Mg on the block, as shown in the figure. Assume that the friction force between the block and the overhang is large enough to keep the block at rest.

2uizynq.jpg


a. Make a free-body diagram of the block, indicating all external forces acting on it.

b. What are the normal force N and the friction forces F that the overhang exerts on the block?

c. Show that the overhang θ can be at most 45◦ if there is any chance that the setup is static.

d. Suppose the coefficient of friction is µ. For what range of angles θ does the block in fact remain at rest?

Homework Equations


(F⃗ net)x = ΣFx = 0

(F⃗ net)y = ΣFy = 0

fs≤μsN

The Attempt at a Solution


[/B]
a.
24fcs1t.jpg


b.
$$ \Sigma F_x=0 => N= Mgcos\theta-Mgsin\theta$$
$$ \Sigma F_y=0 => F_f= Mgcos\theta+Mgsin\theta$$
and also $$ F_f= \mu*N= \mu*Mg(cos\theta-sin\theta) $$

c.
I'm not sure what am I supposed to do…
Is it enough to state that in order that the friction will be positive the term (cos θ -sin θ) has to be positive.
Therefore for 0 < θ < 45 => 0 < (cos θ -sin θ) < 1 ?

d.
$$ F_{f(max)}= \mu*N \geq Mg(cos\theta+sin\theta) $$
$$\mu*Mg(cos\theta-sin\theta) \geq Mg(cos\theta+sin\theta) $$
$$\mu*cos\theta-cos\theta) \geq sin\theta+\mu*sin\theta $$
$$\mu-1 \geq tan\theta-\mu* tan\theta $$
$$\frac{\mu-1}{1-\mu} \geq tan\theta $$
$$-1 \geq tan\theta $$
then i get
$$90 \geq \theta \geq 135 $$
but it make no sense according to the previous section...

Thanks a lot :)
 
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In part b), reconsider your "and also". What are you assuming there that is beyond the information given?
Your answer to c) is on the right lines, but the logic sequence doesn't quite work. Start with "if theta > 45o then..."
Your algebra for d) has a sign error in the fourth line. Correct that and get a new expression for bounds on tan theta as a function of mu.
 
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