Help with Integrating and Finding Concavity of a Curve

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SUMMARY

The discussion focuses on integrating the function (1/(1+t^2)) from 0 to x^2 and determining the concavity of the resulting curve. The integral is identified as arctan(t), which is the antiderivative of the integrand. Participants emphasize the necessity of using trigonometric substitution for solving the integral effectively. The conclusion highlights that recognizing the integrand as the derivative of arctan simplifies the integration process.

PREREQUISITES
  • Understanding of definite integrals
  • Familiarity with trigonometric functions and substitutions
  • Knowledge of the arctangent function and its properties
  • Basic calculus concepts, including concavity and derivatives
NEXT STEPS
  • Study trigonometric substitution techniques in calculus
  • Learn about the properties and applications of the arctan function
  • Explore methods for determining concavity of functions
  • Practice solving definite integrals involving trigonometric functions
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Students studying calculus, particularly those focusing on integration techniques and curve analysis, as well as educators looking for examples of trigonometric substitution in definite integrals.

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Homework Statement


Not real good with the easy text stuff yet so ill give it a shot.

definite integral of (1/(1+t^2))dt from 0 to x^2
then find the interval for which the curve is concave upward.

I totally forgot how to integrate problems like this. It is some sort of substitution I know.

Help?

Would the integral of this involve a natural log?
 
Last edited:
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What you have in your integral is arctan. Probably something you should memorize.
 
You'd need a trigonometric substitution for that integral. It works out quite neatly in the end.

Or recognise that the integrand is the derivative of arctan.
 
Last edited:

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