Help with Rigid Body Exercise: Determine Speed of B

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SUMMARY

The discussion centers on solving a rigid body exercise involving the determination of the speed of point B based on the downward speed of point C, which is given as 0.2 m/s. The initial approach involves using the equation V_c = V_{cm} + ω × R_{c/q} to find the angular velocity (ω) and subsequently the speed of B. However, a key insight from a participant suggests that the problem is fundamentally geometric rather than physics-based, recommending the use of geometric relationships between angles θ and φ to derive the necessary relationships.

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Telemachus
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Homework Statement


Hi there, I'm starting with rigid body, and I'm having some trouble with it, so I'll need your help :D

I have this exercise now, but I will probably come with some others later.

The exercise says: The collars A and C glide along the vertical rods and B of the horizontal. If C has a downward speed of 0.2m/seg. when it reaches plotted to determine the angular velocity of the rod AB.

attachment.php?attachmentid=30305&stc=1&d=1291333079.gif


So, what I think I have to do at first, is to determine the speed of B. Is this right? so I've proceeded this way:

[tex]V_c=V_{cm}+\omega\times{R_{c/q}}[/tex]

[tex]R_{c/q}=25\cos45º \hat{i}+25\sin45º \hat{j}[/tex]

With this I would find the omega between B and C, and then the speed of B.
[tex]V_B=V_{cm}+\omega\times{R_{b/q}}[/tex]

What you say?

Bye there and thanks for your help :)

PD: Sorry for the pic. The vertical rods are larger :P
 

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Hi Telemachus! :smile:

(a bit late, I know, but perhaps this will help)
Telemachus said:
So, what I think I have to do at first, is to determine the speed of B. Is this right? so I've proceeded this way*…

No, I wouldn't do it that way at all.

You're treating this as a physics problem, with centre of mass etc.

It isn't, it's purely a geometry problem …

call the two angles θ and φ, and find the geometric relation between them.

Then differentiate that to get dφ/dθ :smile:
 
Thanks tiny!
 

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