Help with simple linear algebra/quadratic equation proof

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To prove that if ax^2 + bx + c = 0 for all x, then a, b, and c must all equal zero, one can substitute specific values for x, such as 0, 1, and -1, leading to a system of three equations. Solving these equations reveals that the only solution is a = 0, b = 0, and c = 0. This approach simplifies the proof process, making it accessible for beginners in linear algebra. The discussion emphasizes the effectiveness of substituting values to derive conclusions in polynomial equations. Understanding this method can enhance problem-solving skills in algebra.
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Q: Show that if ax^2 + bx + c = 0 for all x, then a=b=c=0

Please help, I'm just starting out in Linear Algebra and I'm not sure how to even start going about proving this. Thanks!
 
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drestupinblac said:
Q: Show that if ax^2 + bx + c = 0 for all x, then a=b=c=0

Please help, I'm just starting out in Linear Algebra and I'm not sure how to even start going about proving this. Thanks!
Welcome to Physics Forums!

If ax^2 + bx + c = 0 for all x, it's certainly true for, say, x = 0, x = 1, and x = -1. Substitute those values in your equation to get three equations in three unknowns, and solve for the three unknowns.
 
Thank you for the warm welcome :) The answer seems almost obvious now that I see it, I guess I didn't think it would be as easy as choosing values for x.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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