Help with Solving a Cauchy-Euler Differential Equation

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To solve the Cauchy-Euler differential equation x²y'' + xy' + 4y = 0, the characteristic equation yields roots r = ±2i. The general solution involves complex exponentials, expressed as y = C1x^(2i) + C2x^(-2i). To eliminate the imaginary components, the solution can be rewritten using Euler's formula, resulting in y = C cos(2 log(x)) + D sin(2 log(x)). This transformation effectively converts the complex solution into a form with real-valued functions. Understanding this method allows for the application of constant coefficient techniques to Cauchy-Euler equations.
Jim4592
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Homework Statement



x2 y'' + x y' + 4 y = 0


Homework Equations



y = xr
y' = r xr-1
y'' = (r2-r)xr-2

The Attempt at a Solution



x2{(r2-r)xr-1} + x{r xr-1} + 4xr

r2 - r + r + 4

r2 + 4 = 0

r = +- 2i

y = C1x2i + c2x-2i

My question is how can i remove the imaginary number with cos[] and sin[]
If you could be as descriptive as possible i'd really appreciate it!

Thanks in advanced!
 
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Use the definition of exponentiation: xa=ea log x.
 
In fact, the substitution y= ln(x) will change any "Cauchy-Euler" equation into an equation with constant coefficients with the same characteristic equation. An equation with constant coefficients, with \pm 2 as characteristic roots, has general solution C cos(2y)+ D sin(2y).
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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