Help with Solving a Cauchy-Euler Differential Equation

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SUMMARY

The discussion focuses on solving the Cauchy-Euler differential equation given by x²y'' + xy' + 4y = 0. The solution involves substituting y = xr, leading to the characteristic equation r² + 4 = 0, yielding complex roots r = ±2i. The general solution is expressed as y = C1x²i + C2x⁻²i. To eliminate the imaginary components, the solution can be rewritten using trigonometric functions: y = C cos(2 log x) + D sin(2 log x), leveraging the relationship between exponentiation and logarithms.

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  • Familiarity with characteristic equations and complex roots
  • Knowledge of trigonometric identities and their applications in differential equations
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Jim4592
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Homework Statement



x2 y'' + x y' + 4 y = 0


Homework Equations



y = xr
y' = r xr-1
y'' = (r2-r)xr-2

The Attempt at a Solution



x2{(r2-r)xr-1} + x{r xr-1} + 4xr

r2 - r + r + 4

r2 + 4 = 0

r = +- 2i

y = C1x2i + c2x-2i

My question is how can i remove the imaginary number with cos[] and sin[]
If you could be as descriptive as possible i'd really appreciate it!

Thanks in advanced!
 
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Use the definition of exponentiation: xa=ea log x.
 
In fact, the substitution y= ln(x) will change any "Cauchy-Euler" equation into an equation with constant coefficients with the same characteristic equation. An equation with constant coefficients, with [itex]\pm 2[/itex] as characteristic roots, has general solution C cos(2y)+ D sin(2y).
 

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