Help with Statics -- Moment of a Couple

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SUMMARY

The discussion focuses on calculating the moment of a couple in statics, specifically using the equation M = F x r. The user describes their approach of finding perpendicular distances between force vectors and using vector products, but expresses confusion regarding the application of these principles to different problems. They highlight the importance of considering both components of forces and their respective perpendicular distances, noting that the magnitude of a couple is derived from the algebraic sum of the couples of each component. The user ultimately seeks clarity on the relationship between force components and their distances.

PREREQUISITES
  • Understanding of vector components in physics
  • Familiarity with the concept of moments in statics
  • Knowledge of the vector product and its application
  • Ability to calculate perpendicular distances in force systems
NEXT STEPS
  • Study the principles of moments in statics using "Engineering Mechanics: Statics" by J.L. Meriam and L.G. Kraige
  • Learn about the vector product in detail, focusing on its application in calculating moments
  • Explore examples of couples and their moments in various force systems
  • Review problems involving force components and their perpendicular distances for better understanding
USEFUL FOR

Students studying engineering mechanics, particularly those focusing on statics, as well as educators seeking to clarify concepts related to moments and force systems.

Frankenstein19
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Homework Statement


This is the problem I'm having problems with.
2016-09-25 (4).png

Homework Equations


M=F x r

The Attempt at a Solution



Let me explain what I've been doing with the practice problems before it, because I fear I may have the wrong understanding.

2016-09-25.png


For this exercise I just found the perpendicular distance between the couple vectores and put the vectors in cartersian form, then I used the vector product. I know the solution is right there but this is what I did when doing it on my own and got the same result.

2016-09-25 (1).png

I thught I had managed to do this exercise fairly easily but now its confusing me because I think it is similar to the one I'm having probles with but when I try to apply similar steps I'm not getting the correct result. For this one again I found the perpendicular distances between the couple vectors and then multiplied them to get the moment. I thought I had understood why only some components made couples but now I'm confused with the x components of the 50lb force. I thought that since it was in the same direction as the perpendiclar distance that they didn't make a couple but then I noticed that there's a 1ft perpendicular distance. Perhanps it's because the distance isn't BETWEEN THEM?

2016-09-25 (3).png

Again I was able to do this one easy peasy by finding the distance between the vectors and using vector product.

2016-09-25 (4).png

Now back to this one. I separated each force into its components. I THOUGHT the perpendicular distanceof the 5kN forces was 3m and the perp distance of F was 1, but that didn't work out and I'm not getting the result. I saw a solution online

upload_2016-9-25_11-35-47.png

I don't understand why they are using both components and why two components of different vectors, say the x components of the F vector and the x component of the 5kN vector, they have the same distance, WHHYYY? Why can't I apply the same logic as before?
 

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Yes the magnitude of a couple is force times perpendicular distance, but in your case the perp distance is not readily determined, so it is easier to break up the force into its x and y components. Then the magnitude of a couple is the algebraic sum of the couples of each component. Note in your example that the x component forces also have a perp distance between them because of the 1 m separation. The solution clearly shows this.
,
 

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