Help with Understanding D-T Fusion for Class Project

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    Class Fusion Project
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Discussion Overview

The discussion revolves around understanding D-T (deuterium-tritium) fusion, specifically focusing on the mathematical calculations related to binding energy and net energy output. Participants explore the discrepancies in energy output calculations and the factors influencing these results, including atomic masses and initial particle energies.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related

Main Points Raised

  • Tom seeks clarification on the calculations for D-T fusion energy output, noting a discrepancy between his result (17.1 MeV) and the commonly cited value (17.6 MeV).
  • One participant suggests that Tom must share his calculations to identify potential mistakes.
  • Tom provides a summary of his calculations, indicating the atomic masses used before and after the fusion reaction.
  • Another participant points out an error in Tom's atomic mass for helium-4, suggesting it should be 4.00260323 amu instead of the value he used.
  • Tom acknowledges using the mass of an alpha particle and discusses the exclusion of electrons in nuclear reactions.
  • A participant emphasizes the importance of using nuclear masses consistently and removing electrons from all relevant isotopes.
  • Tom recalculates using corrected nuclear masses and arrives at a value of approximately 17.59 MeV.
  • Tom expresses gratitude for the assistance and inquires about potential reasons for the remaining discrepancy in energy output.
  • Another participant suggests that initial particle velocities could account for the difference and highlights the need for precision in significant figures when dealing with small energy values.
  • One participant asserts that their calculations yield the expected 17.6 MeV, attributing discrepancies to possible inaccuracies in Tom's sources.

Areas of Agreement / Disagreement

The discussion reveals multiple competing views regarding the correct atomic masses and the factors affecting energy output calculations. Participants do not reach a consensus on the exact cause of the discrepancies, indicating ongoing uncertainty.

Contextual Notes

Participants mention the importance of using accurate atomic masses and significant figures, but there are unresolved questions about the sources of these values and their potential inaccuracies.

Who May Find This Useful

This discussion may be useful for students and enthusiasts interested in nuclear fusion, energy calculations, and the importance of precision in scientific measurements.

toml42
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I need a bit of help here, as part of a class project i was trying to explain how fusion, binding energy, reactors etc work. I always like to go a bit more indepth than the syllabus requires, and i wanted an explanation of how D-T fusion worked mathematically, to clearly show how the binding energy becomes output energy - however, whenever i do the calculations, i don't get the same net energy output as I find online, 17.6 MeV. I always end up with about 17.1.
I tried to compensate for the initial energies, relativistic masses and the coulomb barrier, but I'm still not a huge deal closer. Can anyone give me any clues as to what i may be missing? If nothing is obvious i'll add a brief of summary of the calculations i did.
Thanks, Tom.
 
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Well there is no way that we can see what misstake you made if you not show us your work.
 
Ok, I'll give a brief summary, i was just wondering if I'd missed something face slappingly obvious. this is before i started trying to correct it with extra bits, they didn't help a huge amount.

BEFORE
Deutrium 2.013004633
Tritium 3.01550062
Total 5.028505253

AFTER
Helium 4.0015
Neutron 1.008664917
Total 5.010164917

Missing amu 0.018340336
In kg 3.04548E-29
E = MC2
energy 2.73714E-12

MeV 17.08
 
He-4 atomic mass is 4.00260323 amu, there is your error.
 
i used the mass of an alpha particle, which explains the difference, because the electrons shouldn't be involved in a nuclear reaction should they?
 
then you must remove the electrons from the deuterim and tritium also. Remember that what is listes are ofte the ATOMIC masses. So one must be careful...and cosistent.

Yes you are right, in reality (in a fusion reactor) only nuclei takes part in the reaction.

Also: Post course work / homework questions in appropirate home work forum, this forum is not for those kind of questions which can be read here: https://www.physicsforums.com/showthread.php?t=171607
 
I did remove the electrons from them too, sorry, i should have made that clearer. I didn't think to post it in the homework area because it isn't part of my syllabus, this is more of an outside concern really.
 
ok in that case:

nuclear masses before=
5.02905362 amu

Nuclear masses after=
5.010170986 amu

gives 17.58906 MeV
 
Right, thanks, that's close enough, and when i use those values it works with my calculations. my values for atomic mass must have been slightly off... for future reference, where do you go to find yours?
Thanks for your help, Tom.
 
  • #11
Thanks so much for your help, that website is really usefull! just out of interest though, can you think of anything that might account for the slight discrepancy we're still getting?

My calculations say that if the particles were traveling at about 2.5 million metres per second at the start of the reaction that would be enough extra energy to account for it... that sounds like a reasonable enough speed for high energy particles in a 100,000,000 K fusion reactor... am i on the right lines here maybe?
 
Last edited:
  • #12
1. The source you have ARE already listing nuclear masses and you substract the electron mass again..

2. Lack of accurateness, use ALL significant figures that you can. 17MeV is a very very small unit (3% of electron mass, and one electron is 1/1800 of a nucleon), so be careful!

3. The source you used have listed totally wrong numbers for atomic masses.

With the numbers I used, I got 17.6MeV, which is what the answer tells you.
 

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