- #1
pzzldstudent
- 44
- 0
We were given the hint to try using the Squeeze Theorem in order to find the
limit as n → ∞ of the sequence {(2^n + 3^n)^(1/n)}.
I understand the concept of the squeeze theorem that I need to find functions A and B such that A ≤ {(2^n + 3^n)^(1/n)} ≤ B, and A and B limit to the same quantity, say "L."
So lim A = lim B = L, so that I can conclude that lim (2^n + 3^n)^(1/n) = L.
I don't know how to come up with those functions. It has been 2 years since I last took a calculus class, so I am very rusty with limits.
So far all I have is that 0 ≤ {(2^n + 3^n)^(1/n)} ≤ 2^n + 3^n.
So I can say 0 limits to 0, but then how would I evaluate
the limit of 2^n + 3^n as n approaches ∞? It would just keep getting bigger so I would have that limit as ∞. So I am stuck with 0 and ∞ as limits which is wrong because A and B are supposed to limit to the same value.
Any help, tips, corrections, and/or suggestions is greatly appreciated.
Thank you for your time!
limit as n → ∞ of the sequence {(2^n + 3^n)^(1/n)}.
I understand the concept of the squeeze theorem that I need to find functions A and B such that A ≤ {(2^n + 3^n)^(1/n)} ≤ B, and A and B limit to the same quantity, say "L."
So lim A = lim B = L, so that I can conclude that lim (2^n + 3^n)^(1/n) = L.
I don't know how to come up with those functions. It has been 2 years since I last took a calculus class, so I am very rusty with limits.
So far all I have is that 0 ≤ {(2^n + 3^n)^(1/n)} ≤ 2^n + 3^n.
So I can say 0 limits to 0, but then how would I evaluate
the limit of 2^n + 3^n as n approaches ∞? It would just keep getting bigger so I would have that limit as ∞. So I am stuck with 0 and ∞ as limits which is wrong because A and B are supposed to limit to the same value.
Any help, tips, corrections, and/or suggestions is greatly appreciated.
Thank you for your time!