A tire is filled with air at 15 C and is at a gauge pressure of 220 kPa. If the air temperature goes to 46 C, what fraction of the original air must be released to maintain the original pressure?(adsbygoogle = window.adsbygoogle || []).push({});

Here is what I did:

15 + 273 = 288

46 + 273 = 319

PV = nRT

P1V1 = (n1)288

P2V2 = (n2)319

(n1)288 = (n2)319

(n1) * 288/319 = (n2)

288/319 = .90 so (n2) is 90 percent of (n1), and 10 percent should be removed.

Does this look right?

Thanks Very Much!

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# Homework Help: Help with what is probably an easy question please. Pressure Problem

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