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Help with what is probably an easy question please. Pressure Problem

  1. Dec 12, 2005 #1
    A tire is filled with air at 15 C and is at a gauge pressure of 220 kPa. If the air temperature goes to 46 C, what fraction of the original air must be released to maintain the original pressure?

    Here is what I did:

    15 + 273 = 288
    46 + 273 = 319

    PV = nRT

    P1V1 = (n1)288

    P2V2 = (n2)319

    (n1)288 = (n2)319

    (n1) * 288/319 = (n2)

    288/319 = .90 so (n2) is 90 percent of (n1), and 10 percent should be removed.

    Does this look right?

    Thanks Very Much!
     
  2. jcsd
  3. Dec 12, 2005 #2

    LeonhardEuler

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    Gold Member

    That all looks right to me. The only assumption we need to make for your method to be correct is that the volume of the tires does not change, which seems reasonable.
     
  4. Dec 12, 2005 #3
    Thanks very much LeonhardEuler!

    This is for class, and I still have time, so if anyone else can see a problem with it, please let me know.

    Thank you.
     
  5. Dec 12, 2005 #4
    Just to add one thing... is the method of keeping n in the equation as I did correct?

    Thanks again.
     
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