Thermodynamics Pressure Calculation

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Homework Help Overview

The discussion revolves around a thermodynamics problem involving the calculation of the total translational kinetic energy (KE) of helium atoms in a spherical balloon. The balloon's dimensions, temperature, and pressure are provided, and the original poster is attempting to apply the ideal gas law and kinetic theory to arrive at the correct answer.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the translational KE using the formula KE=3/2kT and questions whether they are using the correct temperature scale and values in their calculations. They also explore the ideal gas law to find the number of molecules.

Discussion Status

The discussion includes attempts to clarify the calculations and assumptions made regarding temperature and the application of formulas. Some participants engage with the original poster's reasoning, but there is no explicit consensus or resolution reached in the thread.

Contextual Notes

The original poster expresses uncertainty about whether to use Kelvin for temperature and questions the correctness of their calculations, indicating potential confusion about the application of thermodynamic principles.

mexqwerty
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A spherical balloon is filled with helium atoms (Note: 1 atm = 101.3 kPa).
What is the total translational KE of the atoms if the balloon has a diameter 26.0 cm at 46.0 °C and the pressure inside the balloon is 121.6 kPa?

The answer is 1680J but I can't get it.

I used KE=3/2kT (in J/molecule) and then multiplied that number by the number of molecules PV=nRT. Am I working it out wrong or using the wrong numbers (like should I use Kelvin for temperatures)?

KE=3/2*1.38x10^-23*46 =2.4x10^21
V= 4/3*pi *radius^3 =4/3*pi*(13/100)^3 =9.2*10^-3
n=PV/RT = (121.6*9.2x10^-3)/(8.314*(46+273)) Not sure if I should use Kelvin here
n= 4.22x10^-4
KE*n = 2.4x10^21* 4.22x10^-4=1x10^18J (which is so off the right answer).
 
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Oops. Somehow my thread got posted twice...? Sorry...
I don't know how to delete...
 
never mind. I got it. Thanks for looking anyway.
 
mexqwerty said:
Oops. Somehow my thread got posted twice...? Sorry...
I don't know how to delete...

Click on Edit button, look for Delete button.

Note that Edit is active only for a limited period of time, if you will wait for too long, posts is no longer editable.
 

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